On the water. The flow is high
enough that very little temperature drop through the radiators is required to
remove the heat from the engine. Q = (mass flow)*(heat-capacity)*(delta-T). If
you increase the mass flow, you decrease the deltaT. I get about a 5*F
delta T on the radiators, on the other hand, the air coming out of the rads is
about 100F higher than the air going in.
Bill,
Further to my query yesterday; putting
some numbers on the 5o DT gives me this:
With 35 gpm, engine power is 55 hp with
pure water; 40 hp with 50/50 water/EG.
160 hp would require 103 gpm with pure
water, 143 with 50/50 water/EG.
What am I missing?
Al