X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from fed1rmmtao107.cox.net ([68.230.241.39] verified) by logan.com (CommuniGate Pro SMTP 5.3.7) with ESMTP id 4316163 for flyrotary@lancaironline.net; Sun, 16 May 2010 10:08:09 -0400 Received-SPF: none receiver=logan.com; client-ip=68.230.241.39; envelope-from=alventures@cox.net Received: from fed1rmimpo02.cox.net ([70.169.32.72]) by fed1rmmtao107.cox.net (InterMail vM.8.00.01.00 201-2244-105-20090324) with ESMTP id <20100516140733.EZIN1969.fed1rmmtao107.cox.net@fed1rmimpo02.cox.net> for ; Sun, 16 May 2010 10:07:33 -0400 Received: from BigAl ([174.65.188.54]) by fed1rmimpo02.cox.net with bizsmtp id JE5o1e00C1ArRLm04E5okt; Sun, 16 May 2010 10:05:48 -0400 X-VR-Score: 0.00 X-Authority-Analysis: v=1.1 cv=RDGknaWEColYBAosNzHWAUqP/VR6Ab6kioi0WieaKDU= c=1 sm=1 a=zk8b5mKjuVwA:10 a=ood2b7iyd8MA:10 a=KDuwdIr/YLANGuoY0nAeCQ==:17 a=R8cDFmMZRXOOxCOeL9EA:9 a=nRa7oya62TZxuaqnTBqPu7_pw-IA:4 a=CjuIK1q_8ugA:10 a=kfM4X8_UwOklokxHbxgA:9 a=896CHULU_zEgE_DZ3wIA:7 a=90EqMXtTsOavWE-xOE6eqDGQgUEA:4 a=KDuwdIr/YLANGuoY0nAeCQ==:117 X-CM-Score: 0.00 From: "Al Gietzen" To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] Re: alternative water pump Date: Sun, 16 May 2010 07:07:05 -0800 Message-ID: <710A233645E5438D9090F56FC86E6FBF@BigAl> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0015_01CAF4C6.6457AD50" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6856 Importance: Normal X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.5931 Thread-index: Acr0M1RmQ3Hh5E6KRqigL55QLQ/c+AA1KfYg In-reply-to: This is a multi-part message in MIME format. ------=_NextPart_000_0015_01CAF4C6.6457AD50 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable On the water. The flow is high enough that very little temperature drop through the radiators is required to remove the heat from the engine. Q = =3D (mass flow)*(heat-capacity)*(delta-T). If you increase the mass flow, = you decrease the deltaT. I get about a 5*F delta T on the radiators, on the other hand, the air coming out of the rads is about 100F higher than the = air going in. Bill, Further to my query yesterday; putting some numbers on the 5o DT gives = me this: With 35 gpm, engine power is 55 hp with pure water; 40 hp with 50/50 water/EG. =20 160 hp would require 103 gpm with pure water, 143 with 50/50 water/EG. =20 What am I missing? =20 Al =20 =20 =20 =20 ------=_NextPart_000_0015_01CAF4C6.6457AD50 Content-Type: text/html; charset="us-ascii" Content-Transfer-Encoding: quoted-printable

On the water. The flow is = high enough that very little temperature drop through the radiators is = required to remove the heat from the engine. Q =3D (mass = flow)*(heat-capacity)*(delta-T). If you increase the mass flow, you decrease the deltaT. I get about a = 5*F delta T on the radiators, on the other hand, the air coming out of the = rads is about 100F higher than the air going in.

Bill,

Further to my query yesterday; = putting some numbers on the 5^oD<= font size=3D2 color=3Dblue face=3DVerdana>T gives me this:

With 35 gpm, engine power is 55 = hp with pure water; 40 hp with 50/50 water/EG.

160 hp would require 103 gpm with = pure water, 143 with 50/50 water/EG.

What am I = missing?

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