Sure you can.
Wt x V / 33000 = HP
Wt = weight in Lbs
V = climb rate in Ft/Min
33000 = Ft-Lbs/Min per HP
1800 x 1000 / 33000 = 54.5 HP
Keep in mind that's the NET HP . . . after engine
efficiency, propeller efficiency and drag.
Wolfgang
----- Original Message -----
Sent: Friday, October 04, 2013 7:32
AM
Subject: RE: [LML] Re: LNC2 flaps at
Reflex
Hmmmm,
If you don’t know the
HP that your engine is developing how would you go about discovering it?
Can you determine HP by climb rate at a known
weight?
B2
From:
Lancair Mailing List
[mailto:lml@lancaironline.net] On Behalf Of
Sky2high@aol.com Sent: Thursday, October 03, 2013 5:04
PM To: lml@lancaironline.net Subject: [LML] Re: LNC2 flaps at
Reflex
Let's see, using
an isosceles triangle where the long sides represent the distance from
the hinge center to the TE. Then the similar right triangles formed
within the isosceles triangle would result in the following
calc:
2 x sin(.5 x angle)
x side = tip movement or 2 x sin ((10-7)/2) x 11.75" = .61" = chord of
the arc of movement.
In a message dated
10/3/2013 3:37:59 P.M. Central Daylight Time, n5276j@aol.com
writes:
My TE to the
center of the hinge is 11.75" what would you guess the measurement up from
the faired in position is to get the -10 degrees? You are right there is
play on the small tailed 320-360.
-----Original
Message----- From: Sky2high <Sky2high@aol.com> To: lml
<lml@lancaironline.net> Sent: Thu, Oct 3, 2013 8:18 am Subject:
[LML] LNC2 flaps at Reflex
One small
point. On the ground the flaps are adjusted and faired in at -7
degrees. In flight the effective angle is different as the flaps are
reflexed further up by air loads that may well result in -10 degrees.
This may be simulated on the ground by manually lifting the trailing
edge of the flap with it at its electrically powered fully reflexed
position and measuring that angle as the effective flight
angle. Don't be timid in lifting the
TE.
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