X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Sat, 05 Oct 2013 17:04:49 -0400 Message-ID: X-Original-Return-Path: Received: from hrndva-omtalb.mail.rr.com ([71.74.56.122] verified) by logan.com (CommuniGate Pro SMTP 6.0.7) with ESMTP id 6503668 for lml@lancaironline.net; Sat, 05 Oct 2013 12:25:25 -0400 Received-SPF: none receiver=logan.com; client-ip=71.74.56.122; envelope-from=Wolfgang@MiCom.net X-Original-Return-Path: X-Authority-Analysis: v=2.0 cv=X9jQ2Rve c=1 sm=0 a=MHZY6FYWMEQOp7S43i2QIw==:17 a=3Zlka_XeuxsA:10 a=aPZri2_z9DQA:10 a=ttCsPuSJ-FAA:10 a=rTjvlri0AAAA:8 a=KGjhK52YXX0A:10 a=-eBSqvl9iTsA:10 a=Ia-xEzejAAAA:8 a=3oc9M9_CAAAA:8 a=hydDS7hDtVj9pDMIzm8A:9 a=wPNLvfGTeEIA:10 a=EzXvWhQp4_cA:10 a=U8Ie8EnqySEA:10 a=SSmOFEACAAAA:8 a=pedpZTtsAAAA:8 a=eEgcZLYj4nZF8CwY4xQA:9 a=gKO2Hq4RSVkA:10 a=UiCQ7L4-1S4A:10 a=_W_S_7VecoQA:10 a=frz4AuCg-hUA:10 a=eJojReuL3h0A:10 a=U_o7C12jc09-syet:21 a=MHZY6FYWMEQOp7S43i2QIw==:117 X-Cloudmark-Score: 0 X-Authenticated-User: X-Originating-IP: 74.218.201.50 Received: from [74.218.201.50] ([74.218.201.50:1205] helo=lobo) by hrndva-oedge01.mail.rr.com (envelope-from ) (ecelerity 2.2.3.46 r()) with ESMTP id 43/B0-06271-25D30525; Sat, 05 Oct 2013 16:24:51 +0000 X-Original-Message-ID: <11256C10812345D39B6A74917A7B03A9@lobo> From: "Wolfgang" X-Original-To: References: Subject: Re: [LML] Re: LNC2 flaps at Reflex X-Original-Date: Sat, 5 Oct 2013 12:24:43 -0400 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0069_01CEC1C5.DEE39D20" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.5512 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.5512 This is a multi-part message in MIME format. ------=_NextPart_000_0069_01CEC1C5.DEE39D20 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Sure you can. Wt x V / 33000 =3D HP Wt =3D weight in Lbs V =3D climb rate in Ft/Min 33000 =3D Ft-Lbs/Min per HP 1800 x 1000 / 33000 =3D 54.5 HP Keep in mind that's the NET HP . . . after engine efficiency, propeller = efficiency and drag. Wolfgang ----- Original Message -----=20 From: Bill Bradburry=20 To: lml@lancaironline.net=20 Sent: Friday, October 04, 2013 7:32 AM Subject: RE: [LML] Re: LNC2 flaps at Reflex Hmmmm, =20 If you don't know the HP that your engine is developing how would you = go about discovering it? Can you determine HP by climb rate at a known = weight? =20 B2 =20 -------------------------------------------------------------------------= ----- From: Lancair Mailing List [mailto:lml@lancaironline.net] On Behalf Of = Sky2high@aol.com Sent: Thursday, October 03, 2013 5:04 PM To: lml@lancaironline.net Subject: [LML] Re: LNC2 flaps at Reflex =20 Steve, =20 Let's see, using an isosceles triangle where the long sides represent = the distance from the hinge center to the TE. Then the similar right = triangles formed within the isosceles triangle would result in the = following calc: =20 2 x sin(.5 x angle) x side =3D tip movement or 2 x sin ((10-7)/2) x = 11.75" =3D .61" =3D chord of the arc of movement.=20 =20 Thus, about .6" =20 Grayhawk =20 In a message dated 10/3/2013 3:37:59 P.M. Central Daylight Time, = n5276j@aol.com writes: GrayHawk, =20 My TE to the center of the hinge is 11.75" what would you guess the = measurement up from the faired in position is to get the -10 degrees? = You are right there is play on the small tailed 320-360. =20 Steve Alderman N25SA -----Original Message----- From: Sky2high To: lml Sent: Thu, Oct 3, 2013 8:18 am Subject: [LML] LNC2 flaps at Reflex One small point. On the ground the flaps are adjusted and faired in = at -7 degrees. In flight the effective angle is different as the flaps = are reflexed further up by air loads that may well result in -10 = degrees. This may be simulated on the ground by manually lifting the = trailing edge of the flap with it at its electrically powered fully = reflexed position and measuring that angle as the effective flight = angle. Don't be timid in lifting the TE. =20 Grayhawk =20 ------=_NextPart_000_0069_01CEC1C5.DEE39D20 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
Sure you can.
 
Wt x V / 33000 =3D HP
 
Wt =3D weight in Lbs
V =3D climb rate in Ft/Min
33000 =3D Ft-Lbs/Min per = HP
 
1800 x 1000 / 33000 =3D 54.5 = HP
 
Keep in mind that's the NET HP . . . = after engine=20 efficiency, propeller efficiency and drag.
 
Wolfgang
 
----- Original Message -----
From:=20 Bill=20 Bradburry
Sent: Friday, October 04, 2013 = 7:32=20 AM
Subject: RE: [LML] Re: LNC2 = flaps at=20 Reflex

Hmmmm,

 

If you = don=92t know the=20 HP that your engine is developing how would you go about discovering = it? =20 Can you determine HP by climb rate at a known=20 weight?

 

B2

 

From:=20 Lancair Mailing List=20 [mailto:lml@lancaironline.net] On = Behalf Of=20 Sky2high@aol.comSent: Thursday, October 03, = 2013 5:04=20 PM
To: lml@lancaironline.net
Subject: [LML] Re: LNC2 flaps = at=20 Reflex

 

Steve,

 

Let's see, = using=20 an isosceles triangle where the long sides represent the distance = from=20 the hinge center to the TE.  Then the similar right triangles = formed=20 within the isosceles triangle would result in the following=20 calc:

 

2 x sin(.5 = x angle)=20 x side =3D tip movement or 2 x sin ((10-7)/2) x 11.75" =3D = .61" =3D chord of=20 the arc of movement. 

 

Thus, = about=20 .6"

 

Grayhawk

 

In a = message dated=20 10/3/2013 3:37:59 P.M. Central Daylight Time, n5276j@aol.com=20 writes:

GrayHawk,

 

My TE to = the=20 center of the hinge is 11.75" what would you guess the measurement = up from=20 the faired in position is to get the -10 degrees? You are right = there is=20 play on the small tailed 320-360.

 

Steve=20 Alderman  N25SA

-----Original=20 Message-----
From: Sky2high <Sky2high@aol.com>
To: lml=20 <lml@lancaironline.net>
Sent: Thu, Oct 3, 2013 8:18 = am
Subject:=20 [LML] LNC2 flaps at Reflex

One = small=20 point.  On the ground the flaps are adjusted and faired in = at -7=20 degrees.  In flight the effective angle is different as the = flaps are=20 reflexed further up by air loads that may well result in -10 = degrees. =20 This may be simulated on the ground by manually lifting the = trailing=20 edge of the flap with it at its electrically powered fully = reflexed=20 position and measuring that angle as the effective flight=20 angle.  Don't be timid in lifting the=20 TE.

 

Grayhawk  =20 =

<= /DIV> ------=_NextPart_000_0069_01CEC1C5.DEE39D20--