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OOPS....Can't get it back
If we assume W=10^3 lbs., V=10^2 knots, N=1 Then
the braking energy per wheel by that formula is
E=0.44 X 10^3 X 10^2 X 10^2=0.44 X 10^7=4.4 X 10^6
lb-ft
If we look at the kinetic energy per wheel, then
the braking energy per wheel is
E=1/2 WV^2
W=pounds "mass"=10^3
V=100 knots=170 feet/second
E=1/2 X 10^3 X 170 X 170=14.5 X 10^6
(over 3 X more)
What gives?
Eric
----- Original Message -----
Sent: Thursday, November 13, 2003 3:24
PM
Subject: [LML] Re: Braking Energy
Jeff,
Braking energy per wheel can be calculate as
follows
Kinetic Energy = (.044 x W x V x V) / N
W =
Landing weight in lbs
V = Landing speed in knots
N = Number of wheels
with brakes
I had a lot of trouble with the original brakes on my
LNC360MKII until I replaced them with "Grove" brakes. They make all the
difference in the world. I don't know what the IVP has but if it
anything like the 360 replacement may be a good solution. Talk to Grove
1-619-562-1268 and see what they have for the IVP.
Good luck
Ray
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