X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from omr-d06.mx.aol.com ([205.188.109.203] verified) by logan.com (CommuniGate Pro SMTP 6.0.8) with ESMTPS id 6723193 for lml@lancaironline.net; Fri, 07 Feb 2014 16:14:15 -0500 Received-SPF: pass receiver=logan.com; client-ip=205.188.109.203; envelope-from=Sky2high@aol.com Received: from mtaomg-mce01.mx.aol.com (mtaomg-mce01.mx.aol.com [172.29.27.207]) by omr-d06.mx.aol.com (Outbound Mail Relay) with ESMTP id B1ED570000092 for ; Fri, 7 Feb 2014 16:13:39 -0500 (EST) Received: from core-mlc005b.r1000.mail.aol.com (core-mlc005.r1000.mail.aol.com [172.29.188.211]) by mtaomg-mce01.mx.aol.com (OMAG/Core Interface) with ESMTP id 6F65F38000089 for ; Fri, 7 Feb 2014 16:13:39 -0500 (EST) From: Sky2high@aol.com Full-name: Sky2high Message-ID: <7a180.59a97dd3.4026a683@aol.com> Date: Fri, 7 Feb 2014 16:13:39 -0500 (EST) Subject: Re: [LML] Re: Fw: [LML] Re: Angle of attack To: lml@lancaironline.net MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="part1_7a180.59a97dd3.4026a683_boundary" X-Mailer: AOL 9.6 sub 168 X-Originating-IP: [67.175.156.123] x-aol-global-disposition: G DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=mx.aol.com; s=20121107; t=1391807619; bh=Q0V3s5XbVaa+ZmcBtYAtBTVPhqEj38l67Ne48rHPL5E=; h=From:To:Subject:Message-ID:Date:MIME-Version:Content-Type; b=C/Gqs4Nc0WlPTT0c+qudY9zoDrZ5tFEGBDhKL+wEA7BXC51iE2r5zr6K6mhsdxOvE Xzwf3KJBBrNomnC1uKDdZKmo/QKpc+HEJYnjbybs6Uc0nKhvCelfJXF/n8VCz/tOpr H/XEgW2Tqn4I1k6H9fbPP46Nk2thDZ8g5ZyECTxk= x-aol-sid: 3039ac1d1bcf52f54c8328bd --part1_7a180.59a97dd3.4026a683_boundary Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit Chris, Yep, that's the kind of number I saw, too. Scott In a message dated 2/7/2014 1:08:01 P.M. Central Standard Time, marv@lancair.net writes: Posted for Chris Zavatson : Angle of attack can have a few different definitions. If tied to airframe or airfoil geometry then zero degrees can produce positive lift. To keep the math simple, the zero lift line is used. By definition, when it is at zero angle there is zero lift. Any positive angle produces positive lift. This removes all the variables of the physical geometry such as washout and incidence angles, etc. Down low and fast the 360 needs a lift coefficient of about 0.19 or about 1.9 degrees - referenced to the zero lift line. Chris Zavatson N91CZ 360std http://www.n91cz.net/ > > > On Friday, February 7, 2014 8:59 AM, Douglas Brunner > wrote: > > Question for all the aerodynamicists out there. > > If a plane is flying, its wing must be generating lift. Does a wing >generate lift at a zero degree angle of attack? > > I thought that there must be some positive angle of attack in level flight. > Am I wrong about this? > > And if I am right, shouldn't the angle of attack be set to some small >positive number? > > -----Original Message----- >>From: Sky2high@aol.com >>Sent: Feb 7, 2014 9:46 AM >>To: lml@lancaironline.net >>Subject: [LML] Re: Angle of attack >> >> >>Tom, >> >>Interesting. The wing has wash out so different parts of the wing are > at slightly different AOAs (think propagation of stall). The design has > the longeron at zero degrees at cruise, flaps at reflex (think chord line >from > leading edge to flap TE). Even average angle of incidence doesn't work > because of wing/flap design. Why not use zero, 1 or 2? >> >>Scott krueger >> >>In a message dated 2/7/2014 8:16:45 A.M. Central Standard Time, > n20087@yahoo.com writes: >>> Folks >>> >>>I am about to setup a g3x in my 360. I was wondering if > anybody could tell me what the typical cruise angle of attack might > be >>> >>>Thanks >>> >>>Tom >>>-- >>>For archives and unsub > http://mail.lancaironline.net:81/lists/lml/List.html > -- >For archives and unsub http://mail.lancaironline.net:81/lists/lml/List.html -- For archives and unsub http://mail.lancaironline.net:81/lists/lml/List.html --part1_7a180.59a97dd3.4026a683_boundary Content-Type: text/html; charset="US-ASCII" Content-Transfer-Encoding: quoted-printable
Chris,
 
Yep, that's the kind of number I saw, too.
 
Scott
 
In a message dated 2/7/2014 1:08:01 P.M. Central Standard Time,=20 marv@lancair.net writes:
=



Posted for Ch= ris=20 Zavatson <chris_zavatson@yahoo.com>:

  
 A= ngle=20 of attack can have a few different definitions.  If tied to airframe= =20
or airfoil geometry then zero degrees can produce positive lift. = ; To=20 keep the
math simple, the zero lift line is used.  By definition= ,=20 when it is at zero
angle there is zero lift.  Any positive angle= =20 produces positive lift.  This
removes all the variables of the= =20 physical geometry such as washout and
incidence angles, etc.
 = ;Down=20 low and fast the 360 needs a lift coefficient of about 0.19 or about
= 1.9=20 degrees - referenced to the zero lift line.

 Chris=20 Zavatson
 N91CZ
 360std
 http://www.n91cz.net/

>=20
>
> On Friday, February 7, 2014 8:59 AM, Douglas Brunner=20
><douglasbrunner@earthlink.net>=20 wrote:
>  
> Question for all the aerodynamicists o= ut=20 there.
>
> If a plane is flying, its wing must be generating= =20 lift.  Does a wing
>generate lift at a zero degree angle of= =20 attack?
>
> I thought that there must be some positive angle= of=20 attack in level flight.
> Am I wrong about this?
>
= >=20 And if I am right, shouldn't the angle of attack be set to some small=20
>positive number?
>
> -----Original Message-----=20
>>From: Sky2high@aol.com
>>Sent: Feb 7, 2014 9:46 AM= =20
>>To: lml@lancaironline.net
>>Subject: [LML] Re: Angl= e of=20 attack
>>
>>
>>Tom,=20
>>
>>Interesting.  The wing has wash out so diffe= rent=20 parts of the wing are
> at slightly different AOAs (think propagat= ion=20 of stall).  The design has
> the longeron at zero degrees at= =20 cruise, flaps at reflex (think chord line
>from
> leading e= dge=20 to flap TE).  Even average angle of incidence doesn't work
>= =20 because of wing/flap design.  Why not use zero, 1 or 2?=20
>>
>>Scott krueger
>>
>>In a messag= e=20 dated 2/7/2014 8:16:45 A.M. Central Standard Time,
> n20087@yahoo.= com=20 writes:
>>>  Folks
>>>
>>>= ;I am=20 about to setup a g3x in my 360.  I was wondering if=20
>  anybody could tell me what the typical cruise angle o= f=20 attack might=20
>  be
>>>
>>>Thanks
>>&= gt;
>>>Tom
>>>--
>>>For=20 archives and unsub=20
>  http://mail.lancaironline.net:81/lists/lml/List.html= =20
> --
>For archives and unsub=20 http://mail.lancaironline.net:81/lists/lml/List.html

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