X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Fri, 04 Oct 2013 07:32:44 -0400 Message-ID: X-Original-Return-Path: Received: from blu0-omc3-s14.blu0.hotmail.com ([65.55.116.89] verified) by logan.com (CommuniGate Pro SMTP 6.0.7) with ESMTP id 6501605 for lml@lancaironline.net; Thu, 03 Oct 2013 18:20:39 -0400 Received-SPF: pass receiver=logan.com; client-ip=65.55.116.89; envelope-from=gary21sn@hotmail.com Received: from BLU172-DS16 ([65.55.116.74]) by blu0-omc3-s14.blu0.hotmail.com with Microsoft SMTPSVC(6.0.3790.4675); Thu, 3 Oct 2013 15:20:06 -0700 X-TMN: [ZTQOg+wMCnEW8c2RyodNcpIBOQazcqpE] X-Originating-Email: [gary21sn@hotmail.com] X-Original-Message-ID: X-Original-Return-Path: gary21sn@hotmail.com From: "Gary Edwards" X-Original-To: "Lancair Mailing List" References: Subject: Re: LNC2 flaps at Reflex X-Original-Date: Thu, 3 Oct 2013 15:20:05 -0700 MIME-Version: 1.0 In-Reply-To: Content-Type: multipart/alternative; boundary="----=_NextPart_000_00C4_01CEC04C.0A269030" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: MSN 9 Seal-Send-Time: Thu, 3 Oct 2013 15:20:05 -0700 X-MimeOLE: Produced By MSN MimeOLE V10.50.0019.1000 X-OriginalArrivalTime: 03 Oct 2013 22:20:06.0585 (UTC) FILETIME=[B6D47290:01CEC086] This is a multi-part message in MIME format. ------=_NextPart_000_00C4_01CEC04C.0A269030 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable I would estimate 0.4875" for the additional -3 degrees reflex. It's = based on a factory plans (235 - same wing and flaps) measurement of = 1.625" at the flap trailing edge for -10 degrees reflex.=20 Gary ----- Original Message -----=20 From: Sky2high@aol.com=20 To: lml@lancaironline.net=20 Sent: Thursday, October 3, 2013 2:04 PM Subject: [LML] Re: LNC2 flaps at Reflex Steve, Let's see, using an isosceles triangle where the long sides represent = the distance from the hinge center to the TE. Then the similar right = triangles formed within the isosceles triangle would result in the = following calc: 2 x sin(.5 x angle) x side =3D tip movement or 2 x sin ((10-7)/2) x = 11.75" =3D .61" =3D chord of the arc of movement.=20 Thus, about .6" Grayhawk In a message dated 10/3/2013 3:37:59 P.M. Central Daylight Time, = n5276j@aol.com writes: GrayHawk, My TE to the center of the hinge is 11.75" what would you guess the = measurement up from the faired in position is to get the -10 degrees? = You are right there is play on the small tailed 320-360. Steve Alderman N25SA -----Original Message----- From: Sky2high To: lml Sent: Thu, Oct 3, 2013 8:18 am Subject: [LML] LNC2 flaps at Reflex One small point. On the ground the flaps are adjusted and faired in = at -7 degrees. In flight the effective angle is different as the flaps = are reflexed further up by air loads that may well result in -10 = degrees. This may be simulated on the ground by manually lifting the = trailing edge of the flap with it at its electrically powered fully = reflexed position and measuring that angle as the effective flight = angle. Don't be timid in lifting the TE. Grayhawk ------=_NextPart_000_00C4_01CEC04C.0A269030 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
I would estimate 0.4875" for the additional -3 degrees = reflex.  It's=20 based on a factory plans (235 - same wing and flaps) measurement of = 1.625" at=20 the flap trailing edge for -10 degrees reflex. 
 
Gary
----- Original Message -----
Sent: Thursday, October 3, 2013 = 2:04=20 PM
Subject: [LML] Re: LNC2 flaps = at=20 Reflex

Steve,
 
Let's see, using an isosceles triangle where the long sides=20 represent the distance from the hinge center to the TE.  Then the = similar=20 right triangles formed within the isosceles triangle would result in = the=20 following calc:
 
2 x sin(.5 x angle) x side =3D tip movement or 2 x sin ((10-7)/2) = x 11.75"=20 =3D .61" =3D chord of the arc of movement. 
 
Thus, about .6"
 
Grayhawk
 
In a message dated 10/3/2013 3:37:59 P.M. Central Daylight Time,=20 n5276j@aol.com writes:
GrayHawk,
 
My TE to the center of the hinge is 11.75" what would you guess = the=20 measurement up from the faired in position is to get the -10 = degrees? You=20 are right there is play on the small tailed 320-360.
 
Steve Alderman  N25SA
-----Original=20 Message-----
From: Sky2high <Sky2high@aol.com>
To: lml=20 <lml@lancaironline.net>
Sent: Thu, Oct 3, 2013 8:18 = am
Subject:=20 [LML] LNC2 flaps at Reflex

One small point.  On the ground the flaps are adjusted=20 and faired in at -7 degrees.  In flight the effective = angle is=20 different as the flaps are reflexed further up by air loads that may = well=20 result in -10 degrees.  This may be simulated on the = ground by=20 manually lifting the trailing edge of the flap with it at its = electrically=20 powered fully reflexed position and measuring that angle as the = effective flight angle.  Don't be timid in lifting the = TE.
 
Grayhawk  =20 =
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