X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from omr-d04.mx.aol.com ([205.188.109.201] verified) by logan.com (CommuniGate Pro SMTP 6.0.7) with ESMTPS id 6501526 for lml@lancaironline.net; Thu, 03 Oct 2013 17:04:38 -0400 Received-SPF: pass receiver=logan.com; client-ip=205.188.109.201; envelope-from=Sky2high@aol.com Received: from mtaomg-db01.r1000.mx.aol.com (mtaomg-db01.r1000.mx.aol.com [172.29.51.199]) by omr-d04.mx.aol.com (Outbound Mail Relay) with ESMTP id 51B9870047C69 for ; Thu, 3 Oct 2013 17:04:02 -0400 (EDT) Received: from core-mtb004a.r1000.mail.aol.com (core-mtb004.r1000.mail.aol.com [172.29.234.205]) by mtaomg-db01.r1000.mx.aol.com (OMAG/Core Interface) with ESMTP id 23084E000088 for ; Thu, 3 Oct 2013 17:04:02 -0400 (EDT) From: Sky2high@aol.com Full-name: Sky2high Message-ID: <71562.237802cd.3f7f35c0@aol.com> Date: Thu, 3 Oct 2013 17:04:00 -0400 (EDT) Subject: Re: [LML] Re: LNC2 flaps at Reflex To: lml@lancaironline.net MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="part1_71562.237802cd.3f7f35c0_boundary" X-Mailer: AOL 9.6 sub 168 X-Originating-IP: [67.175.156.123] x-aol-global-disposition: G DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=mx.aol.com; s=20121107; t=1380834242; bh=m5OmQpAjaDkUN1j9BzDh6aScYyHy9iHTnXkLie0wTfs=; h=From:To:Subject:Message-ID:Date:MIME-Version:Content-Type; b=ZSnaRthQ03Rttl14Kjg/JvKJofvIXsOzhjmxN4tTvF1szJkyxaRySZf9IEzm0Xv9b +w9shuocGJ+cuV8MhPZm40TFYWADQ7uEVzVB/jnDEb2+ibHhfXjyXujzAoljRmiu6N DFzEIon9IXLIMAnEGGP+6xrVR21ICIXTbmU3Wjzc= x-aol-sid: 3039ac1d33c7524ddbc23aa7 --part1_71562.237802cd.3f7f35c0_boundary Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit Steve, Let's see, using an isosceles triangle where the long sides represent the distance from the hinge center to the TE. Then the similar right triangles formed within the isosceles triangle would result in the following calc: 2 x sin(.5 x angle) x side = tip movement or 2 x sin ((10-7)/2) x 11.75" = .61" = chord of the arc of movement. Thus, about .6" Grayhawk In a message dated 10/3/2013 3:37:59 P.M. Central Daylight Time, n5276j@aol.com writes: GrayHawk, My TE to the center of the hinge is 11.75" what would you guess the measurement up from the faired in position is to get the -10 degrees? You are right there is play on the small tailed 320-360. Steve Alderman N25SA -----Original Message----- From: Sky2high To: lml Sent: Thu, Oct 3, 2013 8:18 am Subject: [LML] LNC2 flaps at Reflex One small point. On the ground the flaps are adjusted and faired in at -7 degrees. In flight the effective angle is different as the flaps are reflexed further up by air loads that may well result in -10 degrees. This may be simulated on the ground by manually lifting the trailing edge of the flap with it at its electrically powered fully reflexed position and measuring that angle as the effective flight angle. Don't be timid in lifting the TE. Grayhawk --part1_71562.237802cd.3f7f35c0_boundary Content-Type: text/html; charset="US-ASCII" Content-Transfer-Encoding: quoted-printable
Steve,
 
Let's see, using an isosceles triangle where the long sides repre= sent=20 the distance from the hinge center to the TE.  Then the similar right= =20 triangles formed within the isosceles triangle would result in the followin= g=20 calc:
 
2 x sin(.5 x angle) x side =3D tip movement or 2 x sin ((10-7)/2) x 11= .75" =3D=20 .61" =3D chord of the arc of movement. 
 
Thus, about .6"
 
Grayhawk
 
In a message dated 10/3/2013 3:37:59 P.M. Central Daylight Time,=20 n5276j@aol.com writes:
=
GrayHawk,
 
My TE to the center of the hinge is 11.75" what would you guess the= =20 measurement up from the faired in position is to get the -10 degrees? You= are=20 right there is play on the small tailed 320-360.
 
Steve Alderman  N25SA
---= --Original=20 Message-----
From: Sky2high <Sky2high@aol.com>
To: lml=20 <lml@lancaironline.net>
Sent: Thu, Oct 3, 2013 8:18 am
Subjec= t:=20 [LML] LNC2 flaps at Reflex

One small point.  On the ground the flaps are adjusted=20 and faired in at -7 degrees.  In flight the effective angle is= =20 different as the flaps are reflexed further up by air loads that may well= =20 result in -10 degrees.  This may be simulated on the ground by= =20 manually lifting the trailing edge of the flap with it at its electricall= y=20 powered fully reflexed position and measuring that angle as the effe= ctive=20 flight angle.  Don't be timid in lifting the TE.
 
Grayhawk  =20
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