X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Fri, 30 Dec 2005 15:39:35 -0500 Message-ID: X-Original-Return-Path: Received: from systems3.net ([68.98.211.24] verified) by logan.com (CommuniGate Pro SMTP 5.0.5) with ESMTPS id 906234 for lml@lancaironline.net; Fri, 30 Dec 2005 10:35:16 -0500 Received-SPF: none receiver=logan.com; client-ip=68.98.211.24; envelope-from=cberland@systems3.net Received: from systems0d3b724 ([192.168.1.81]) by systems3.net (8.13.4/8.13.4/Debian-3) with SMTP id jBUFWTeV010893 for ; Fri, 30 Dec 2005 08:32:30 -0700 X-Original-Message-ID: <00ba01c60d56$a60e2050$5101a8c0@systems0d3b724> From: "Craig Berland" X-Original-To: "Lancair Mail List" Subject: [LML] Re: Where has all the power gone? X-Original-Date: Fri, 30 Dec 2005 08:35:17 -0700 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_00B7_01C60D1B.F67B1F60" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2800.1506 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1506 X-Virus-Scanned: ClamAV 0.86.2/1219/Wed Dec 28 15:57:59 2005 on systems3.net X-Virus-Status: Clean This is a multi-part message in MIME format. ------=_NextPart_000_00B7_01C60D1B.F67B1F60 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Rob wrote: I think you are considering torque here rather than energy or = power. You need to factor the rotation of the crank shaft into your = integral. Then you will get the same result as the simple piston = pressure/displacement annalysis. I wish there was a way to express tone with the written language. I'm = intrigued by your thoughts...I'm not being argumentative. If there was = no friction....no momentum.... and the fuel burn was = instantaneous...wouldn't the engine simply stop at TDC? The force would = be infinite straight down through the piston, rod and crank....?? If you want to get a head ache...contemplate moving the piston = centerline to the ATDC side of the crank, thus producing a slight rod = angle at TDC. Craig Berland ------=_NextPart_000_00B7_01C60D1B.F67B1F60 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable

Rob wrote: I think you are considering torque here rather than = energy or=20 power. You need to factor the rotation of the crank shaft into your = integral.=20 Then you will get the same result as the simple piston = pressure/displacement=20 annalysis.

I wish there was a way to express tone with the written = language. I'm=20 intrigued by your thoughts...I'm not being argumentative. If there = was no=20 friction....no momentum.... and the fuel burn was = instantaneous...wouldn't the=20 engine simply stop at TDC? The force would be infinite straight = down=20 through the piston, rod and crank....??

If you want to get a head ache...contemplate moving the piston = centerline=20 to the ATDC side of the crank, thus producing a slight rod angle at = TDC.

Craig Berland

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