X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Fri, 30 Dec 2005 15:39:35 -0500 Message-ID: X-Original-Return-Path: Received: from secure5.liveoakhosting.com ([64.49.254.21] verified) by logan.com (CommuniGate Pro SMTP 5.0.5) with ESMTPS id 906272 for lml@lancaironline.net; Fri, 30 Dec 2005 11:28:10 -0500 Received-SPF: none receiver=logan.com; client-ip=64.49.254.21; envelope-from=walter@advancedpilot.com Received: (qmail 23816 invoked from network); 30 Dec 2005 10:27:11 -0600 Received: from ip68-108-237-23.br.no.cox.net (HELO ?10.0.1.4?) (68.108.237.23) by rs5.liveoakhosting.com with SMTP; 30 Dec 2005 10:27:11 -0600 Mime-Version: 1.0 (Apple Message framework v623) In-Reply-To: References: Content-Type: multipart/alternative; boundary=Apple-Mail-6-886476043 X-Original-Message-Id: <3f9fa23ed944d07f4332c5510a97ee96@advancedpilot.com> From: Walter Atkinson Subject: Re: [LML] Where has all the power gone? X-Original-Date: Fri, 30 Dec 2005 10:26:22 -0600 X-Original-To: "Lancair Mailing List" X-Mailer: Apple Mail (2.623) --Apple-Mail-6-886476043 Content-Transfer-Encoding: quoted-printable Content-Type: text/plain; charset=ISO-8859-1; format=flowed Bill: Your supposition is correct. But, the change in effective timing=20 between 2500 and 2200 rpms is very small. In most cases, the prop is=20 more efficient at 2200 rpms. Walter On Dec 29, 2005, at 9:01 PM, Bill&Sue wrote: Dumb question for you smart guys. =A0 I've been reading all of the spark timing information with great=20 interest. We have a while before we have to settle on an ignition=20 system for our non TC 550 and, of course, would like to make the most=20 informed decision. Soooo, George, Scott, Hamid, Paul, Rick, et al, how=20= about this: =A0 Seems to me that rpm changes effectively=A0adjust ignition timing. For=20= example, if you're running at 2500 rpm and the spark occurs at 25 btc,=20= the flame propagates at a rate that produces max pressure at some point=20= after tdc, lets just say 15 degrees. If you reduced the rpm to 2200 and=20= the spark occurred at 25 btc the flame would propagate at the same rate=20= as before but the piston is moving slower. Seems to me that the max=20 pressure would occur at somewhere less than 15 after tdc, effectively=20 advancing the ignition. =A0 Most agree that the majority of the advantage of adjusting spark=20 timing=A0happens at lower power settings. To me, it looks like the=20 advantage is better fuel economy as opposed to more power. Couldn't one=20= simply pull the prop control back to gain this same advantage? =A0 Probably lots of flaws in my thinking, but I'm not smart enough to see=20= 'em. Help me out. =A0 Bill Harrelson 5zq@cox.net N5ZQ 320 1,100+ hrs N6ZQ=A0 IV=A0 4.239% =A0 =A0 =A0= --Apple-Mail-6-886476043 Content-Transfer-Encoding: quoted-printable Content-Type: text/enriched; charset=ISO-8859-1 Bill: Your supposition is correct. But, the change in effective timing between 2500 and 2200 rpms is very small. In most cases, the prop is more efficient at 2200 rpms. Walter On Dec 29, 2005, at 9:01 PM, Bill&Sue wrote: ArialDumb question for you smart guys. =A0 ArialI've been reading all of the spark timing information with great interest. We have a while before we have to settle on an ignition system for our non TC 550 and, of course, would like to make the most informed decision. Soooo, George, Scott, Hamid, Paul, Rick, et al, how about this: =A0 ArialSeems to me that rpm changes effectively=A0adjust ignition timing. For example, if you're running at 2500 rpm and the spark occurs at 25 btc, the flame propagates at a rate that produces max pressure at some point after tdc, lets just say 15 degrees. If you reduced the rpm to 2200 and the spark occurred at 25 btc the flame would propagate at the same rate as before but the piston is moving slower. Seems to me that the max pressure would occur at somewhere less than 15 after tdc, effectively advancing the ignition. =A0 ArialMost agree that the majority of the advantage of adjusting spark timing=A0happens at lower power settings. To me, it looks like the advantage is better fuel economy as opposed to more power. Couldn't one simply pull the prop control back to gain this same advantage? =A0 ArialProbably lots of flaws in my thinking, but I'm not smart enough to see 'em. Help me = out. =A0 ArialBill = Harrelson = Arial0000,0000,FFFF5zq@cox.net ArialN5ZQ 320 1,100+ = hrs ArialN6ZQ=A0 IV=A0 = 4.239% =A0 =A0 =A0= --Apple-Mail-6-886476043--