Return-Path: Sender: (Marvin Kaye) To: lml Date: Thu, 19 Sep 2002 21:54:25 -0400 Message-ID: X-Original-Return-Path: Received: from fire.phys.cmu.edu ([128.2.26.129] verified) by logan.com (CommuniGate Pro SMTP 4.0b7) with ESMTP id 1737775 for lml@lancaironline.net; Thu, 19 Sep 2002 21:25:50 -0400 Received: from localhost (jbp@localhost) by fire.phys.cmu.edu (8.11.6/8.11.6) with ESMTP id g8K1P4O15348 for ; Thu, 19 Sep 2002 21:25:04 -0400 X-Original-Date: Thu, 19 Sep 2002 21:25:03 -0400 (EDT) From: Jeffery Peterson X-Original-To: lancair mail list Subject: Re: Ram Air X-Original-Message-ID: MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII Fred: Thanks for the very thorough posting. One thing has always puzzled me: The air enters the small aperture of the scoop at some fraction of the true air speed...fast. Then the air moves to a larger cross section, and so it must slow down (since mass flow is unchanging). That means the pressure rises, according to Mr. Bernoulli's equation. All this I believe I understand. But the problem I have is that the hole in the carb throat is about the size of the scoop enterance. doesnt the air have to speed back up again to get through the carb? So the pressure falls and we are back where we started. I'm confused. Help. -Jeff Peterson LCN2...N273CK...90%