Return-Path: Received: from imf16aec.mail.bellsouth.net ([205.152.59.64] verified) by logan.com (CommuniGate Pro SMTP 4.2b2) with ESMTP id 3210293 for flyrotary@lancaironline.net; Fri, 07 May 2004 07:54:23 -0400 Received: from [68.212.167.142] by imf16aec.mail.bellsouth.net (InterMail vM.5.01.06.08 201-253-122-130-108-20031117) with ESMTP id <20040507115422.LIJE19568.imf16aec.mail.bellsouth.net@[68.212.167.142]> for ; Fri, 7 May 2004 07:54:22 -0400 User-Agent: Microsoft-Entourage/10.1.4.030702.0 Date: Fri, 07 May 2004 07:54:10 -0400 Subject: Re: [FlyRotary] Re: fuel injector prices From: Bulent Aliev To: Rotary motors in aircraft Message-ID: In-Reply-To: Mime-version: 1.0 Content-type: text/plain; charset="US-ASCII" Content-transfer-encoding: 7bit On 5/6/04 11:31 PM, "John Slade" wrote: >> 550 cc/min = 0.1453 Gallons. So 0.1453 Gallons * 60 (minutes) = 8.718 >> Gallons/ hour x 6 (lbs/gallon) = 52 lbs/ hr. Or a 550 cc/min >> injector would >> flow approx 52 lbs of fuel if it flowed wide open for one hour or >> 52 lbs/hr. >> >> for the NA engines the stock injector is the 460 cc/min (sometimes they >> varied a bit around that figure) >> 460 cc/min = 0.1215191gallons so performing the same >> calculations = 7.29114 >> gallons/hr x 6 = 43.75 lbs/hour > > Ed. > Thanks. I follow that. So with 4 of these 550cc suckers going full belt I'd > be capable of expelling 52/6 * 4 = 34.67 gals/hr. Seems a bit excessive! > Also - does fuel pressure factor into the equasion? > John John, I believe it does. If the EC2 controls only the pulse length, Higher pressure will expel larger quantity of fuel than lower pressure for the same injector opening. I don't think the EC2 takes into account the capacity of the injector? Bulent