X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from fmailhost03.isp.att.net ([204.127.217.103] verified) by logan.com (CommuniGate Pro SMTP 6.0.7) with ESMTP id 6505656 for flyrotary@lancaironline.net; Mon, 07 Oct 2013 13:18:42 -0400 Received-SPF: none receiver=logan.com; client-ip=204.127.217.103; envelope-from=bbradburry@bellsouth.net Received: from desktop (adsl-98-85-147-248.mco.bellsouth.net[98.85.147.248]) by isp.att.net (frfwmhc03) with SMTP id <20131007171809H0300pntare>; Mon, 7 Oct 2013 17:18:09 +0000 X-Originating-IP: [98.85.147.248] From: "Bill Bradburry" To: "'Rotary motors in aircraft'" References: In-Reply-To: Subject: Prop and PSRU efficiency Date: Mon, 7 Oct 2013 13:18:18 -0400 Message-ID: MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit X-Mailer: Microsoft Office Outlook 11 Thread-Index: Ac7Db/1f+h03dDTpRU+d1QBxASUhTgADz35w X-MimeOLE: Produced By Microsoft MimeOLE V6.0.6002.18463 I have asked this question a couple of times and no one has hazarded a guess. How much HP is lost from our engines due to the PSRU? I have been interested in determining what the HP output of my engine is and that info would be needed for that estimation. They tell me that most props are about 80-85% efficient, so to calculate the hp, you take the difference between your climb rate and your glide descent rate at the same airspeed, multiplied by the weight, and then divided by 33000. Wt * V / 33000 = HP This would be the prop HP, so to get the prop flange HP, you would divide by the prop efficiency, between .8 and .85. To get the engine flywheel HP, you would have to add something for the loss of the PSRU. Is anyone willing to take a shot at that number?? Third or forth chance! :>) Bill B