Received-SPF: none
 receiver=logan.com; client-ip=68.230.241.39; envelope-from=dale.r@cox.net
Message-ID: <4788CDF1.70005@cox.net>
Date: Sat, 12 Jan 2008 07:25:53 -0700
From: Dale Rogers <dale.r@cox.net>
User-Agent: Thunderbird 2.0.0.9 (Windows/20071031)
MIME-Version: 1.0
To: Rotary motors in aircraft <flyrotary@lancaironline.net>
Subject: Re: [FlyRotary] Re: Angles
References: <list-2642079@logan.com>
In-Reply-To: <list-2642079@logan.com>
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Content-Transfer-Encoding: 7bit

But Joe, any triangle can be divided into two right triangles.

Dale R.

Joe Ewen wrote:
> For those who may use this formula, this formula will only work on a 
> right triangle.  Please correct me if I am wrong.
> Joe
>  
>  
>
>     ----- Original Message -----
>     *From:* Ed Anderson <mailto:eanderson@carolina.rr.com>
>     *To:* Rotary motors in aircraft <mailto:flyrotary@lancaironline.net>
>     *Sent:* Saturday, January 12, 2008 8:30 AM
>     *Subject:* [FlyRotary] Re: Angles
>
>     Hi George,
>      
>     Several folks have responded to your question concerning angles,
>     for what it is worth I also got 5.729 degrees.
>      
>     There are a couple of formulas you can use.  One common approach
>     is to use
>     ArcSin, but unless you have a convenient ArcSin function available
>     that can be problematic.
>      
>     So instead I like to use this one for y/r (y being the vertical
>     length of your angle and r the horizontal length)   Degrees = y/r
>     * 180/pi   = 3/30*180/3.1456 =  5.729 deg.  This way you don't
>     need a table/function of ArcSin.
>      
>     Ed
>      
>