X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from rg5.comporium.net ([208.104.2.25] verified) by logan.com (CommuniGate Pro SMTP 5.2c4) with ESMTPS id 2642081 for flyrotary@lancaironline.net; Sat, 12 Jan 2008 08:58:02 -0500 Received-SPF: pass receiver=logan.com; client-ip=208.104.2.25; envelope-from=Jewen@comporium.net Received: from 208-104-81-95.lnhe.2wcm.comporium.net (HELO engineer1) ([208.104.81.95]) by rg5.comporium.net (MOS 3.8.4-GA FastPath queued) with SMTP id AJT13276; Sat, 12 Jan 2008 08:57:22 -0500 (EST) Message-ID: <005d01c85522$c9db4a60$6505a8c0@cooleygroup.local> From: "Joe Ewen" To: "Rotary motors in aircraft" References: Subject: Re: [FlyRotary] Re: Angles Date: Sat, 12 Jan 2008 08:55:27 -0500 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_005A_01C854F8.E06CABE0" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.3138 X-MIMEOLE: Produced By Microsoft MimeOLE V6.00.2900.3138 X-Junkmail-Status: score=10/70, host=rg5.comporium.net X-Junkmail-SD-Raw: score=unknown, refid=str=0001.0A010205.4788C742.0054,ss=1,fgs=0, ip=208.104.81.95, so=2007-03-13 10:31:19, dmn=5.4.3/2007-11-16 This is a multi-part message in MIME format. ------=_NextPart_000_005A_01C854F8.E06CABE0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable For those who may use this formula, this formula will only work on a = right triangle. Please correct me if I am wrong. Joe ----- Original Message -----=20 From: Ed Anderson=20 To: Rotary motors in aircraft=20 Sent: Saturday, January 12, 2008 8:30 AM Subject: [FlyRotary] Re: Angles Hi George, Several folks have responded to your question concerning angles, for = what it is worth I also got 5.729 degrees. There are a couple of formulas you can use. One common approach is to = use=20 ArcSin, but unless you have a convenient ArcSin function available = that can be problematic. So instead I like to use this one for y/r (y being the vertical length = of your angle and r the horizontal length) Degrees =3D y/r * 180/pi = =3D 3/30*180/3.1456 =3D 5.729 deg. This way you don't need a = table/function of ArcSin. Ed ----- Original Message -----=20 From: George Lendich=20 To: Rotary motors in aircraft=20 Sent: Friday, January 11, 2008 7:42 PM Subject: [FlyRotary] Angles Ed, I measured the taper of the flywheel taper with a ruler, the draft = is 3mm in 30mm. I checked that with a dial indicator and it was correct = - how does one derive the angle of that? Is it 6 degrees? George (down under) ------=_NextPart_000_005A_01C854F8.E06CABE0 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
For those who may use this formula, = this formula=20 will only work on a right triangle.  Please correct me if I am=20 wrong.
Joe
 
 
----- Original Message -----
From:=20 Ed=20 Anderson
Sent: Saturday, January 12, = 2008 8:30=20 AM
Subject: [FlyRotary] Re: = Angles

Hi George,
 
Several folks have responded to your question = concerning=20 angles, for what it is worth I also got 5.729 degrees.
 
There are a couple of formulas you can = use.  One=20 common approach is to use
ArcSin, but unless you have a = convenient=20 ArcSin function available that can be problematic.
 
So instead I like to use this one for y/r = (y being=20 the vertical length of your angle and r the horizontal=20 length)   Degrees =3D y/r * 180/pi   =3D = 3/30*180/3.1456=20 =3D  5.729 deg.  This way you = don't need=20 a table/function of ArcSin.
 
Ed
 
----- Original Message -----
From:=20 George Lendich
To: Rotary motors in = aircraft=20
Sent: Friday, January 11, = 2008 7:42=20 PM
Subject: [FlyRotary] = Angles

Ed,
I measured the taper of the = flywheel taper with=20 a ruler, the draft is 3mm in 30mm. I checked that with a dial = indicator and=20 it was correct - how does one derive the angle of that?
Is it 6 degrees?
George (down=20 under)
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