X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from cdptpa-omtalb.mail.rr.com ([75.180.132.121] verified) by logan.com (CommuniGate Pro SMTP 5.2c4) with ESMTP id 2642046 for flyrotary@lancaironline.net; Sat, 12 Jan 2008 08:30:14 -0500 Received-SPF: pass receiver=logan.com; client-ip=75.180.132.121; envelope-from=eanderson@carolina.rr.com Received: from edward2 ([24.74.103.61]) by cdptpa-omta06.mail.rr.com with SMTP id <20080112132934.LPGW26668.cdptpa-omta06.mail.rr.com@edward2> for ; Sat, 12 Jan 2008 13:29:34 +0000 Message-ID: <004301c8551f$492be620$2402a8c0@edward2> From: "Ed Anderson" To: "Rotary motors in aircraft" References: Subject: Re: [FlyRotary] Angles Date: Sat, 12 Jan 2008 08:30:23 -0500 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0040_01C854F5.601CA5B0" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.3138 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.3138 This is a multi-part message in MIME format. ------=_NextPart_000_0040_01C854F5.601CA5B0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Hi George, Several folks have responded to your question concerning angles, for = what it is worth I also got 5.729 degrees. There are a couple of formulas you can use. One common approach is to = use=20 ArcSin, but unless you have a convenient ArcSin function available that = can be problematic. So instead I like to use this one for y/r (y being the vertical length = of your angle and r the horizontal length) Degrees =3D y/r * 180/pi = =3D 3/30*180/3.1456 =3D 5.729 deg. This way you don't need a = table/function of ArcSin. Ed ----- Original Message -----=20 From: George Lendich=20 To: Rotary motors in aircraft=20 Sent: Friday, January 11, 2008 7:42 PM Subject: [FlyRotary] Angles Ed, I measured the taper of the flywheel taper with a ruler, the draft is = 3mm in 30mm. I checked that with a dial indicator and it was correct - = how does one derive the angle of that? Is it 6 degrees? George (down under) ------=_NextPart_000_0040_01C854F5.601CA5B0 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
Hi George,
 
Several folks have responded to your question = concerning=20 angles, for what it is worth I also got 5.729 degrees.
 
There are a couple of formulas you can = use.  One=20 common approach is to use
ArcSin, but unless you have a = convenient=20 ArcSin function available that can be problematic.
 
So instead I like to use this one for y/r = (y being=20 the vertical length of your angle and r the horizontal=20 length)   Degrees =3D y/r * 180/pi   =3D = 3/30*180/3.1456=20 =3D  5.729 deg.  This way you = don't need a=20 table/function of ArcSin.
 
Ed
 
----- Original Message -----
From:=20 George=20 Lendich
Sent: Friday, January 11, 2008 = 7:42=20 PM
Subject: [FlyRotary] = Angles

Ed,
I measured the taper of the flywheel = taper with a=20 ruler, the draft is 3mm in 30mm. I checked that with a dial indicator = and it=20 was correct - how does one derive the angle of that?
Is it 6 degrees?
George (down=20 under)
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