X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from fed1rmmtao104.cox.net ([68.230.241.42] verified) by logan.com (CommuniGate Pro SMTP 5.2c1) with ESMTP id 2610985 for flyrotary@lancaironline.net; Sun, 23 Dec 2007 12:34:17 -0500 Received-SPF: none receiver=logan.com; client-ip=68.230.241.42; envelope-from=alventures@cox.net Received: from fed1rmimpo02.cox.net ([70.169.32.72]) by fed1rmmtao104.cox.net (InterMail vM.7.08.02.01 201-2186-121-102-20070209) with ESMTP id <20071223173338.KEUR18222.fed1rmmtao104.cox.net@fed1rmimpo02.cox.net> for ; Sun, 23 Dec 2007 12:33:38 -0500 Received: from BigAl ([72.192.143.193]) by fed1rmimpo02.cox.net with bizsmtp id UHZh1Y0014AaN600000000; Sun, 23 Dec 2007 12:33:41 -0500 From: "Al Gietzen" To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] Heat Distribution or 2 rotor??? Date: Sun, 23 Dec 2007 09:34:30 -0800 Message-ID: <001401c8458a$12f09820$6401a8c0@BigAl> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0015_01C84547.04CD5820" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6626 Importance: Normal In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.3198 This is a multi-part message in MIME format. ------=_NextPart_000_0015_01C84547.04CD5820 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable Ed; =20 I scanned the graph I have of the heat balance on the rotary. Even = after cropping it is about 2 MB. I attached a version scaled down to about 250 = KB, but it bounced. I'll send this without the chart and then send a = further reduced chart. If it is not sufficiently legible I can send you the big version direct. =20 Way back when I applied this and didn't fully understand what I was = doing, I used the values where the arrows are; which I guess would be for quite a leaned condition. Probably best to design cooling system based on = something close to stochiemetric (1.0). =20 If the graph is unreadable; the breakdown of the energy of the fuel = going in; for A/F ratio of 1.0, is: =20 39% - out the exhaust 27% - effective useable HP 15% - into the coolant 11% - unburned gases 6% - into the oil 2% - other=20 =20 For the leaned condition; A/F ratio 1.15: =20 42% - out the exhaust 28% - effective useable HP 18% - into the coolant 5% - unburned gases 6% - into the oil 1% - other=20 =20 Al =20 =20 -----Original Message----- From: Rotary motors in aircraft [mailto:flyrotary@lancaironline.net] On Behalf Of Ed Anderson Sent: Sunday, December 23, 2007 5:41 AM To: Rotary motors in aircraft Subject: [FlyRotary] Heat Distribution or 2 rotor??? =20 Some place in a place far away and a long time ago, I had a reference to = the heat distribution of the 13B engine - 2/3 of the waste heat being = rejected by coolant/radiator and 1/3 by the oil system. However, I appear to = have lost that reference, anybody on the list have any source or reference?? =20 Thanks =20 Ed Ed Anderson Rv-6A N494BW Rotary Powered Matthews, NC eanderson@carolina.rr.com http://www.andersonee.com http://members.cox.net/rogersda/rotary/configs.htm#N494BW http://www.dmack.net/mazda/index.html ------=_NextPart_000_0015_01C84547.04CD5820 Content-Type: text/html; charset="us-ascii" Content-Transfer-Encoding: quoted-printable

Ed;

 

I scanned the graph I have of the = heat balance on the rotary.  Even after cropping it is about 2 MB. I = attached a version scaled down to about 250 KB, but it bounced.  I’ll = send this without the chart and then send a further reduced chart.  If it is = not sufficiently legible I can send you the big version = direct.

 

Way back when I applied this and didn’t fully understand what I was doing, I used the values where = the arrows are; which I guess would be for quite a leaned condition. =  Probably best to design cooling system based on something close to stochiemetric = (1.0).

 

If the graph is unreadable; the breakdown of the energy of the fuel going in; for A/F ratio of 1.0, = is:

 

39% - out the = exhaust

27% - effective useable = HP

15% - into the = coolant

11% - unburned = gases

6%  - into the = oil

2%  - other =

 

For the leaned condition; A/F = ratio 1.15:

 

42% - out the = exhaust

28% - effective useable = HP

18% - into the = coolant

5% - unburned = gases

6%  - into the = oil

1%  - other =

 

Al

 

 

-----Original = Message-----
From: Rotary motors in = aircraft [mailto:flyrotary@lancaironline.net] On Behalf Of Ed Anderson
Sent: Sunday, December 23, 2007 5:41 AM
To: Rotary motors in = aircraft
Subject: [FlyRotary] Heat Distribution or 2 rotor???

 

Some place in a place far = away and a long time ago, I had a reference to the heat distribution of the 13B = engine - 2/3 of the waste heat being rejected by coolant/radiator and 1/3 by the = oil system.  However, I appear to have lost that reference, anybody on = the list have any source or reference??

 

Thanks

 

Ed

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