X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from [64.4.51.75] (HELO hotmail.com) by logan.com (CommuniGate Pro SMTP 4.3c5) with ESMTP id 913968 for flyrotary@lancaironline.net; Mon, 25 Apr 2005 12:44:28 -0400 Received-SPF: pass receiver=logan.com; client-ip=64.4.51.75; envelope-from=lors01@msn.com Received: from mail pickup service by hotmail.com with Microsoft SMTPSVC; Mon, 25 Apr 2005 09:43:42 -0700 Message-ID: Received: from 64.4.51.200 by BAY107-DAV3.phx.gbl with DAV; Mon, 25 Apr 2005 16:43:42 +0000 X-Originating-IP: [64.4.51.200] X-Originating-Email: [lors01@msn.com] X-Sender: lors01@msn.com From: "Tracy Crook" To: "Rotary motors in aircraft" References: Subject: Re: [FlyRotary] Re: Engine timing Date: Mon, 25 Apr 2005 12:43:39 -0400 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_018F_01C54994.67CDDFA0" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: MSN 9 X-MimeOLE: Produced By MSN MimeOLE V9.10.0011.1703 Seal-Send-Time: Mon, 25 Apr 2005 12:43:39 -0400 X-OriginalArrivalTime: 25 Apr 2005 16:43:42.0343 (UTC) FILETIME=[F08A4970:01C549B5] This is a multi-part message in MIME format. ------=_NextPart_000_018F_01C54994.67CDDFA0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Nope. Looking at it from the end where you can see it. This is only a = rough setting because the Mark 1 eyeball is not a precision instrument. = Note that you still need to make some marks on front pulley to find 35 = BTDC. Mark TDC then use basic geometry to find linear distance on = pulley OD equal to desired number of degrees & make second mark at 35 = BTDC. Tracy Okay, position the flywheel counterweight at 9 o'clock. Looking from = what end? Front (pulley end) I presume??? Wendell The sensor should be lined up with the crank at 35 deg BTDC on #1 = rotor. TDC is when the flywheel end counterweight is positioned at = 9:00. =20 I don't think the procedure you mentioned below is correct. Not = sure where the engine would be in your procedure but it is 90 degrees = from TDC in one direction or the other.=20 Tracy ----- Original Message -----=20 From: Wendell Voto=20 To: Rotary motors in aircraft=20 Sent: Monday, April 25, 2005 11:23 AM Subject: [FlyRotary] Re: Engine timing =20 Can't get engine to run, have good spark, injectors are now = working. I believe that the timing is off, don't have timing maks on = pulley so did what the Mazda book said; install crank angle sensor with = the marks lined up and with the ecentric shaft with the keyway at the = top.=20 Got a couple puffs of smoke and couple backfires out the intake. = Any suggestions? Wendell ------=_NextPart_000_018F_01C54994.67CDDFA0 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
Nope.  Looking at it from the end where you can see it.  = This is=20 only a rough setting because the Mark 1 eyeball is not a precision=20 instrument.  Note that you still need to make some marks on front = pulley to=20 find 35 BTDC.  Mark TDC then use basic geometry to find linear = distance on=20 pulley OD equal to desired number of degrees & make second mark at = 35=20 BTDC.
 
Tracy

Okay, position the = flywheel=20 counterweight at 9 o'clock.  Looking from what end? Front (pulley = end) I=20 presume???
Wendell
 
The sensor should be lined up with the crank at 35 deg BTDC on = #1=20 rotor.  TDC is when the flywheel end counterweight is = positioned at=20 9:00. 
 
I don't think the procedure you mentioned below is = correct.  Not=20 sure where the engine would be in your procedure but it is 90=20 degrees from TDC in one direction or the other. 
 
Tracy
----- Original Message ----- =
From: Wendell=20 Voto
To: Rotary motors in = aircraft=20
Sent: Monday, April 25, = 2005 11:23=20 AM
Subject: [FlyRotary] Re: = Engine=20 timing

   
Can't get engine to run, have good spark, injectors are now = working. I believe that the timing is off, don't have timing = maks on=20 pulley so did what the Mazda book said; install crank angle = sensor with=20 the marks lined up and with the ecentric shaft with the keyway = at the=20 top.
Got a couple puffs of smoke and couple backfires out the=20 intake.  Any suggestions?
 
=
Wendell
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