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Hi Eric
Thanks for the comments
In this case, The assumption was made that engines that consume the same
amount of air/flue produce essential equivalent HP. True, the different
BSFC for different engines which will result in a different HP output - but
I was trying to determine if the physical configuration of the pumping might
make a difference.
However, I believe that local inlet velocity does matter - as a narrower
intake/Higher velocity can result in the "choking" of flow at a certain
velocities (there are formulas for determining at what velocity with what
opening that choke point occurs at - but I'll leave that to someone else)
and there is the increased friction loss (how significant I don't know) with
higher velocity and smaller opening.
Average velocity and maximum velocity can be considerably different in an
intake. According to the theory I have read the Maximum instantaneous
velocity in your intake should not exceed mach 0.6 . But, the average
velocity could still could be in the 150-300 ft/sec range.
I agree that Volume of air = velocity * Carb area, however, I think the
dependent and independent variables would cause the equation to be stated
Velocity = Volume of air/Carb area. Since the volume of a positive
displacement pump is independent of the air velocity it would be the
independent variable in the equation. However, to be perfectly correct we
should really talk about air mass flow and not just the velocity as the
density of the intake charge will vary - but, the volume (with a positive
displacement pump) will not. You get the same volumetric displacement from
the engine whether at idle or WOT - its, of course, the density of the air
in the intake that makes the difference in the power produced.
In any case, like I said the Ellison rotary story could be just that - a
story without factual data or perhaps there is something to it. Just trying
to see what might make logical sense in looking at it. Not trying to
discourage anyone from using an Ellison, I would be just as interested as
anyone to see what the real world comparison would be.
Best Regards
Ed
----- Original Message -----
From: "Eric Ruttan" <ericruttan@chartermi.net>
To: "Rotary motors in aircraft" <flyrotary@lancaironline.net>
Sent: Thursday, February 10, 2005 9:18 AM
Subject: [FlyRotary] Re: : Same HP = Same Air Mass <> same air Velocity II
[FlyRotary] Re: Ellison, the missing piece
Warning top poster, who cuts the post size down.
A hopothises for your examination.
A 360 Lyc does not produce the same power as a rotary.
If true, then the Ellison card may not get enough air.
If not true, then there is no real reason why the Ellison cannot feed a
rotary.
Ed, I understand your math, but even if the local inlet velocity is much
higher, we dont care. the velocities adverage out to the same, as the
volume of air = velocity * carb area.
If the velocities are higher, the rotary consumes more air, and makes more
power.
Eric
----- Original Message -----
From: "Ed Anderson" <eanderson@carolina.rr.com>
To: "Rotary motors in aircraft" <flyrotary@lancaironline.net>
Sent: Thursday, February 10, 2005 8:31 AM
Subject: [FlyRotary] : Same HP = Same Air Mass <> same air Velocity II
[FlyRotary] Re: Ellison, the missing piece
Good question, Tom.
That interpretation did occur to me. I think the answer depends on your
assumptions, IF using commonly accepted formulas for calculating air flow
vs
rpm and displacement (and considering both are positive displacement
pumps) - then the 360 CID lycoming turning 2800 rpm and the rotors in the
rotary turning 2100 rpm (6300 rpm E shaft) ingest the same total quantity
of
air in one minute - approx 291 CFM. In comparing the two engines, its
accepted that you compare them over the standard 720deg 4 stroke cycle -
that means that 4 of the rotary faces have gone through their cycle in the
same 720 deg of rotation.
But, assuming the formulas are correct, then they both end up with the
same
amount of air in the engine to create the same HP. I think my math is
correct on the smaller/unit displacement and longer period of rotation for
the rotary for the same intake of air. However, in both cases the air
flow
is pulsating and pulsating differently. So if the total displacement for
the rotary over that 720 deg is less than the Lycoming and the time it
takes
to complete that rotation is slower AND you still ingest the same amount
of
total Air then the only way I can see that happening is the velocity of
the
air in the rotary's intake has to be considerably higher than in the
Lycoming.
The only other alternative answer I see if that the commonly accepted
formula for comparing the rotary to the reciprocating 4 stroke is
incorrect
(I got beat about the head mercilessly by a number of respected rotary
experts challenging that formula , so I wont' go there again (at least
not
now {:>)).
Air Flow = Total Displacement * RPM/(2 - accounting for only every other
cylinder sucking on each rev * 1728 (conversion of cubic inches to cubic
feet) = TD*RPM/(2*1728)
For the 360 CID Lycoming at 2800 rpm, Air Flow = 360*2800/(2*1728) =
291.66
CFM
Using the commonly accepted notion that a rotary is equivalent to a 160
CID
4 stroke reciprocating engine because of the 4 faces of 40 CID that
complete
there cycle in 720 deg.
For the 160 CID Rotary at 6000 rpm, Air Flow = 160 * 6300/(2*1728) =
291.66
CFM
So if both ingest the 291 CFM and the rotary has less total displacement
(over 720 deg) then disregarding any of my math on rotation period
differences you still have to account for why the rotary can ingest the
same
amount of air with less displacement. (Now I must admit I have my
suspicions about the commonly accepted (racing approved) formula for the
rotary. However, if my suspicions about the rotary formula are correct,
it
would make the rotary even more efficient at ingesting air - so I won't go
there {:>)).
If my logic and calculations are correct then this implies the Ve of the
rotary is considerably better than the Lycoming and is great than 100%. I
mentioned a few of the reasons why the Ve of the rotary may indeed be
better
in the previous message.
Now, its possible that the stories about the Ellison not working well on
the
rotary is just that - a story OR there could be a plausible physical
reason
as I have poorly attempted to present.
Ed
----- Original Message -----
From: Tom
To: Rotary motors in aircraft
Sent: Wednesday, February 09, 2005 11:54 PM
Subject: [FlyRotary] Re: Same HP = Same Air Mass <> same air Velocity
[FlyRotary] Re: Ellison, the missing piece
Ed,
>The rotary has 40 CID displacement per face and 2 facesx 2 rotors =
4*40
or 160 CID for one rev. So the rotary has 22% less displacement per
revolution and the longer rotation period.<
and
>So if the rotary has less displacement of the sucking component and
must
take 25% longer for each revolution. Therefore the only way it can obtain
an equal amount of air is for the intake air to have a higher velocity
than
the Lycoming does.<
Isn't 'displacement' equal to the amount of air needing to be ingested?
So 22% less displacement equates to 22% less air and the rotarys longer
rotation period gives it more time for air to push in? And then the
intake air velocity should be lower?
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