Return-Path: <13brv3@bellsouth.net> Received: from imf23aec.mail.bellsouth.net ([205.152.59.71] verified) by logan.com (CommuniGate Pro SMTP 4.2.5) with ESMTP id 593849 for flyrotary@lancaironline.net; Thu, 06 Jan 2005 17:21:20 -0500 Received-SPF: pass receiver=logan.com; client-ip=205.152.59.71; envelope-from=13brv3@bellsouth.net Received: from rd ([65.6.194.9]) by imf23aec.mail.bellsouth.net (InterMail vM.5.01.06.11 201-253-122-130-111-20040605) with ESMTP id <20050106222044.QTIR2378.imf23aec.mail.bellsouth.net@rd> for ; Thu, 6 Jan 2005 17:20:44 -0500 From: "Russell Duffy" <13brv3@bellsouth.net> To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] Re: fluidyne oil cooler Date: Thu, 6 Jan 2005 16:20:58 -0600 Message-ID: <00f901c4f43d$ff6d44b0$6101a8c0@rd> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_00FA_01C4F40B.B4D2D4B0" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6626 Importance: Normal In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 This is a multi-part message in MIME format. ------=_NextPart_000_00FA_01C4F40B.B4D2D4B0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable You should be able to get flow rate; pressure drop; heat rejection = rating from Fluidyne. Based on my calcs, it would be good to about a steady = 120 hp in a rotary, if you get good air flow through it.=20 =20 How can you calculate this without the info you mentioned? How much = air flow is "good". What is the temp? I appreciate the thought, but I = don't really believe all the calculations in the world will give a real answer when you consider all the variables. It might be interesting, and will certainly be in the ballpark, but you won't really know how it works = until you try it. =20 =20 My more simplified way to look at this is that the Fluidyne has the same core volume as the 2nd gen cooler. It is thicker, which reduces the = cooling ability, but I also bet that it's more efficient at rejecting heat. In other words, it seems like it should be about equal to the 2nd gen = cooler. Since lots of folks are running the 2nd gen cooler, and most are pretty happy with it, then I have to believe that this will work at least reasonably well for me. Since it will stand upright under the engine, I should be able to give it a far superior duct to anything I've ever = used. I'm going to try it, but realize that I may take over the record for = number of oil cooler mods from Ed. =20 Cheers, Rusty (abandoned calculus long ago) =20 =20 ------=_NextPart_000_00FA_01C4F40B.B4D2D4B0 Content-Type: text/html; charset="us-ascii" Content-Transfer-Encoding: quoted-printable Message
You should = be able to=20 get flow rate; pressure drop; heat rejection rating from Fluidyne. =  Based=20 on my calcs, it would be good to about a steady 120 hp in a rotary, if = you get=20 good air flow through it. 
 
How can you=20 calculate this without the info you = mentioned?   How much air flow is "good".  = What is the=20 temp?  I = appreciate the=20 thought, but I don't really believe all the calculations in the world = will give=20 a real answer when you consider all the variables.  It might be=20 interesting, and will certainly be in the ballpark, but you won't really = know=20 how it works until you try it.  
 
My more=20 simplified way to look at this is that the Fluidyne has the=20 same core volume as the 2nd gen cooler.  It is = thicker,=20 which reduces the cooling ability, but I also bet that it's more = efficient at=20 rejecting heat.  In other words, it seems like it should be about = equal to=20 the 2nd gen cooler.  Since lots of folks are running the = 2nd gen=20 cooler, and most are pretty happy with it, then I have to believe that = this will=20 work at least reasonably well for me.  Since it will stand upright=20 under the engine, I should be able to give it a far superior duct = to=20 anything I've ever used.  I'm going to try it, but realize that I = may take=20 over the record for number of oil cooler mods from=20 Ed.
 
Cheers,
Rusty (abandoned=20 calculus long ago)   
 
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