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From: Sky2high@aol.com
Full-name: Sky2high
Message-ID: <c7a60.2a98df0f.3ee0c1ae@aol.com>
Date: Wed, 5 Jun 2013 12:30:38 -0400 (EDT)
Subject: Re: [LML] Re: loss of power on takeoff
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Yes Terrence, AOA.  No mental exercise necessary if one has an AOA  sensor. 
 And, Charles' comment is a bit off.
 
In level flight, the wing AOA provides sufficient lift (wing  loading) to 
equal the effect of the force of gravity (1 G) on the  aircraft weight (W).  
Thrust overcomes drag to result in forward  speed. 
 
In a descent at the same speed used in level flight, lift is less than W  
and either power (thrust) is reduced or drag is increased.  Remember that G  
is just for relative reference.
 
Again, in level flight at the same power, but in a coordinated  banked 
turn, the wing AOA has been increased to add enough  bank angle lift necessary 
to maintain 1 G with respect to the vertical.   I.E. The wing load must be 
increased to keep the plane at the same altitude  - The lift has to equal the 
weight divided by the cosine of the bank  angle.  To visualize:
 

One could redraw this with force vectors to see it better.  Of course,  
because of increased load, the induced drag is  also increased.
 
Finally, in a coordinated banked turn without power and even further  drag 
from other bits and pieces, descent (glide) will occur unless the AOA could  
be increased provide sufficient lift to offset the vertical component (the  
pull of gravity).  But, there is a limit AOA at which a stall would occur - 
 thus descent.  In a banked turning descent at a certain speed (best glide  
for the conditions), less lift is required, thus less load on the wing, 
thus a  lower stall speed than a higher load.  This supports the statements  
made by both Dave Morss and myself.  Dave's point is that large bank angle  
conducted at a optimal speed shortens the time (distance) and lessens  the 
altitude loss plus in the descent the stall speed is not as great as  that in 
the same bank holding altitude.  
 
An optimal speed is somewhere above stall speed.  Factors affecting  stall 
speed are load and drag (wheels, flaps, prop, etc.) - hence the  requirement 
that you point the nose down making use of kinetic energy rather  than 
gasoline to keep up the speed.
 
Uh, the Aeronautics for Naval Aviators is silent on powerless descending  
turns (maybe a glider tech manual would be more informative).  I have  
included the simplified Excel spreadsheet to give you a feel for some of  these 
parameters before testing at high altitudes.
 
Blue Skies,
 
Scott Krueger
 
 
In a message dated 6/3/2013 8:29:23 A.M. Central Daylight Time,  
troneill@charter.net writes:

Angle, angle, angle.  Angle of stall is constant, no matter what.  Simpler, 
not requiring mental gymnastics.
Terrence.

Sent from my iPad

On Jun 3, 2013, at 7:03 AM, Charles Brown <_browncc1@verizon.net_ 
(mailto:browncc1@verizon.net) >  wrote:


In a straight ahead descent, the wing is producing 1g lift and the  stall 
speed is the same as in level flight.   You guys may be  thinking of the 
change in stall speed when *initiating* a descent (pushover,  less than 1g for a 
moment), or when *terminating* a descent (pull-up, or  flare, momentarily 
more than 1g).  


On Jun 2, 2013, at 2:18 PM, _Sky2high@aol.com_ (mailto:Sky2high@aol.com)  
wrote:


Dave, et al,
 
In a descent, the stall speed is different because the  wing is not lifting 
the same weight as it would be in level 1-G  flight.  However, that only 
accounts for the vertical  component.  The hi-G turn (like 70 degrees of bank) 
is still  adding sgnificant load to the wings.
 
<...>
 
 
In a message dated 6/2/2013 1:08:44 P.M. Central Daylight Time, 
_morss@pacbell.net_ (mailto:morss@pacbell.net)  writes:

in  scotts reply he includes a graph of stall speeds vrs bank in a level  
turn.remember this turn around maneuver is not level but descending so the  
stall speed doesn't increase as much as the graph but if you get ground  rush 
and try to arrest the descent rate in the turn you will probably  stall
more reason to practice at altitude and see if this is something  you might 
want to include in your bag of tricks
dave
--
For  archives and unsub http://mail.lancaironline.net:81/lists/lml/List.html


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<DIV>Yes Terrence, AOA.&nbsp; No mental exercise necessary if one has an AO=
A=20
sensor.&nbsp; And, Charles' comment is a bit off.</DIV>
<DIV>&nbsp;</DIV>
<DIV>In level flight, the wing&nbsp;AOA provides sufficient lift (wing=20
loading)&nbsp;to equal the effect of the&nbsp;force of gravity (1 G)&nbsp;o=
n the=20
aircraft weight (W).&nbsp; Thrust overcomes drag to result in forward=20
speed.&nbsp;</DIV>
<DIV>&nbsp;</DIV>
<DIV>In a descent at the same speed used in level flight, lift is less than=
 W=20
and either power (thrust) is reduced or drag is increased.&nbsp; Remember t=
hat G=20
is just for relative reference.</DIV>
<DIV>&nbsp;</DIV>
<DIV>Again, in level flight at the same power, but in a coordinated=20
banked&nbsp;turn,&nbsp;the wing&nbsp;AOA has been increased to add&nbsp;eno=
ugh=20
bank angle lift necessary to maintain 1 G with respect to the vertical.&nbs=
p;=20
I.E. The wing load must be increased to keep the plane&nbsp;at the same alt=
itude=20
- The lift has to equal the weight divided by the cosine of the bank=20
angle.&nbsp; To visualize:</DIV>
<DIV>&nbsp;</DIV>
<DIV><IMG SRC=3D"cid:X.MA1.1370449837@aol.com"  style=3D"HEIGHT: 311px; WID=
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<DIV>&nbsp;</DIV>
<DIV>One could redraw this with force vectors to see it better.&nbsp; Of co=
urse,=20
because of increased load,&nbsp;the induced&nbsp;drag is=20
also&nbsp;increased.</DIV>
<DIV>&nbsp;</DIV>
<DIV>Finally, in a coordinated&nbsp;banked turn without power and even furt=
her=20
drag from other bits and pieces, descent (glide) will occur unless the AOA =
could=20
be increased provide sufficient lift to offset the vertical component&nbsp;=
(the=20
pull of gravity).&nbsp; But, there is a limit AOA at which a stall would oc=
cur -=20
thus descent.&nbsp; In a banked turning descent at a certain speed (best gl=
ide=20
for the conditions), less lift is required, thus less load on the wing, thu=
s a=20
lower stall speed&nbsp;than a higher load.&nbsp; This supports the statemen=
ts=20
made by both Dave Morss and myself.&nbsp; Dave's point is that large bank a=
ngle=20
conducted at a optimal speed shortens the time (distance) and lessens=20
the&nbsp;altitude loss plus in the descent the stall speed is not as great =
as=20
that in the same bank holding altitude.&nbsp; </DIV>
<DIV>&nbsp;</DIV>
<DIV>An optimal speed is somewhere above stall speed.&nbsp; Factors affecti=
ng=20
stall speed are load and drag (wheels, flaps, prop, etc.) - hence the=20
requirement that you point the nose down making use of kinetic energy rathe=
r=20
than gasoline to keep up the speed.</DIV>
<DIV>&nbsp;</DIV>
<DIV>Uh, the Aeronautics for Naval Aviators is silent on powerless descendi=
ng=20
turns (maybe a glider tech manual would be more informative).&nbsp; I have=
=20
included the simplified&nbsp;Excel spreadsheet to give you a feel for some =
of=20
these parameters before testing at high altitudes.</DIV>
<DIV>&nbsp;</DIV>
<DIV>Blue Skies,</DIV>
<DIV>&nbsp;</DIV>
<DIV>Scott Krueger</DIV>
<DIV>&nbsp;</DIV>
<DIV>
<DIV>In a message dated 6/3/2013 8:29:23 A.M. Central Daylight Time,=20
troneill@charter.net writes:</DIV>
<BLOCKQUOTE   style=3D"PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: bl=
ue 2px solid"><FONT     style=3D"BACKGROUND-COLOR: transparent" color=3D#00=
0000 size=3D2 face=3DArial>
  <DIV>Angle, angle, angle. &nbsp;Angle of stall is constant, no matter wha=
t.=20
  &nbsp;Simpler, not requiring mental gymnastics.</DIV>
  <DIV>Terrence.<BR><BR>Sent from my iPad</DIV>
  <DIV><BR>On Jun 3, 2013, at 7:03 AM, Charles Brown &lt;<A     title=3Dmai=
lto:browncc1@verizon.net     href=3D"mailto:browncc1@verizon.net">browncc1@=
verizon.net</A>&gt;=20
  wrote:<BR><BR></DIV>
  <BLOCKQUOTE type=3D"cite">
    <DIV>
    <DIV>In a straight ahead descent, the wing is producing 1g lift and the=
=20
    stall speed is the same as in level flight. &nbsp;&nbsp;You guys may be=
=20
    thinking of the change in stall speed when *initiating* a descent (push=
over,=20
    less than 1g for a moment), or when *terminating* a descent (pull-up, o=
r=20
    flare, momentarily more than 1g). &nbsp;</DIV>
    <DIV><BR></DIV><BR>
    <DIV>
    <DIV>On Jun 2, 2013, at 2:18 PM, <A title=3Dmailto:Sky2high@aol.com    =
   href=3D"mailto:Sky2high@aol.com">Sky2high@aol.com</A> wrote:</DIV><BR   =
    class=3DApple-interchange-newline>
    <META name=3DGENERATOR content=3D"MSHTML 10.00.9200.16576">
    <DIV style=3D"FONT-SIZE: 10pt; FONT-FAMILY: Arial; COLOR: #000000"     =
  bottommargin=3D"7" leftmargin=3D"7" rightmargin=3D"7" topmargin=3D"7"><FO=
NT       color=3D#000000 size=3D2 face=3DArial>
    <DIV>Dave, et al,</DIV>
    <DIV>&nbsp;</DIV>
    <DIV>In a descent, the&nbsp;stall speed&nbsp;is different&nbsp;because =
the=20
    wing is not lifting the same weight as it would be in level 1-G=20
    flight.&nbsp; However, that&nbsp;only accounts for&nbsp;the vertical=20
    component.&nbsp; The hi-G turn (like 70 degrees of bank)&nbsp;is still=
=20
    adding sgnificant&nbsp;load to the wings.</DIV>
    <DIV>&nbsp;</DIV>
    <DIV>&lt;...&gt;</DIV>
    <DIV>&nbsp;</DIV>
    <DIV>
    <DIV>In a message dated 6/2/2013 1:08:44 P.M. Central Daylight Time, <A=
       title=3Dmailto:morss@pacbell.net       href=3D"mailto:morss@pacbell.=
net">morss@pacbell.net</A> writes:</DIV>
    <BLOCKQUOTE       style=3D"PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-=
LEFT: blue 2px solid"><FONT         style=3D"BACKGROUND-COLOR: transparent"=
 color=3D#000000 size=3D2 face=3DArial>in=20
      scotts reply he includes a graph of stall speeds vrs bank in a level=
=20
      turn.remember this turn around maneuver is not level but descending s=
o the=20
      stall speed doesn't increase as much as the graph but if you get grou=
nd=20
      rush and try to arrest the descent rate in the turn you will probably=
=20
      stall<BR>more reason to practice at altitude and see if this is somet=
hing=20
      you might want to include in your bag of tricks<BR>dave<BR>--<BR>For=
=20
      archives and unsub <A         title=3Dhttp://mail.lancaironline.net:8=
1/lists/lml/List.html         href=3D"http://mail.lancaironline.net:81/list=
s/lml/List.html">http://mail.lancaironline.net:81/lists/lml/List.html</A></=
FONT></BLOCKQUOTE></DIV></FONT></DIV></DIV><BR></DIV></BLOCKQUOTE></FONT></=
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