X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Sun, 16 Dec 2007 16:19:06 -0500 Message-ID: X-Original-Return-Path: Received: from defout.telus.net ([199.185.220.240] verified) by logan.com (CommuniGate Pro SMTP 5.2c1) with ESMTP id 2582965 for lml@lancaironline.net; Sat, 15 Dec 2007 23:30:33 -0500 Received-SPF: pass receiver=logan.com; client-ip=199.185.220.240; envelope-from=eunder@telus.net Received: from priv-edtnaa04.telusplanet.net ([64.180.3.178]) by priv-edtnes27.telusplanet.net (InterMail vM.7.08.02.02 201-2186-121-104-20070414) with ESMTP id <20071216042956.HWOZ1467.priv-edtnes27.telusplanet.net@priv-edtnaa04.telusplanet.net> for ; Sat, 15 Dec 2007 21:29:56 -0700 Received: from owner8xo2xo7y9 (d64-180-3-178.bchsia.telus.net [64.180.3.178]) by priv-edtnaa04.telusplanet.net (BorderWare MXtreme Infinity Mail Firewall) with SMTP id C0M85FCHP1 for ; Sat, 15 Dec 2007 21:29:52 -0700 (MST) X-Original-Message-ID: <008a01c83f9c$4d30c8f0$b203b440@owner8xo2xo7y9> From: "Eric Underwod" X-Original-To: Subject: Rudder balance X-Original-Date: Sat, 15 Dec 2007 20:29:51 -0800 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0087_01C83F59.3EB7A0C0" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.3138 X-MIMEOLE: Produced By Microsoft MimeOLE V6.00.2900.3198 This is a multi-part message in MIME format. ------=_NextPart_000_0087_01C83F59.3EB7A0C0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Does any one know the percentage of balance for the rudder on the 360. I = know that you are to add 4 lbs. to the counter arm and two half round to = the lower leading edge but were does this put the balance. On my fist = plane I balance the rudder to 100% but is this extra weight that may = not be needed? I thought that I read somewhere that only 80% was = required on the rudder and 100% on the rest. Eric Underwood ------=_NextPart_000_0087_01C83F59.3EB7A0C0 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable

Does any one know the percentage of = balance for the=20 rudder on the 360. I know that you are to add 4 lbs. to the counter arm = and two=20 half round to the lower leading edge but were does this put the balance. = On my=20 fist plane I balance the rudder to 100% but is this extra = weight that=20 may not be needed? I thought that I read somewhere that only 80% was = required on=20 the rudder and 100% on the rest.

Eric Underwood

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