X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Fri, 12 Oct 2007 20:00:03 -0400 Message-ID: X-Original-Return-Path: Received: from mtao01.charter.net ([209.225.8.186] verified) by logan.com (CommuniGate Pro SMTP 5.1.12) with ESMTP id 2384083 for lml@lancaironline.net; Fri, 12 Oct 2007 18:44:09 -0400 Received-SPF: pass receiver=logan.com; client-ip=209.225.8.186; envelope-from=troneill@charter.net Received: from aa04.charter.net ([10.20.200.156]) by mtao01.charter.net (InterMail vM.7.08.02.00 201-2186-121-20061213) with ESMTP id <20071012224324.CAQQ18969.mtao01.charter.net@aa04.charter.net> for ; Fri, 12 Oct 2007 18:43:24 -0400 Received: from axs ([75.132.198.100]) by aa04.charter.net with SMTP id <20071012224324.NQJI1254.aa04.charter.net@axs> for ; Fri, 12 Oct 2007 18:43:24 -0400 X-Original-Message-ID: <003b01c80d21$4c2e6550$6501a8c0@axs> From: "terrence o'neill" X-Original-To: "Lancair Mailing List" References: Subject: Re: [LML] Drag coefficient X-Original-Date: Fri, 12 Oct 2007 17:43:23 -0500 MIME-Version: 1.0 Content-Type: text/plain; format=flowed; charset="iso-8859-1"; reply-type=original Content-Transfer-Encoding: 7bit X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.3138 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.3198 X-Chzlrs: 0 Hi Bob, Thanks for the info on L2 drag. Always heard that windmilling props make a lot more drag than stopped props. I like to use Hoerner's approach in his Fluid Dynamic Drag book... wetted area, with numbers from a variety of complete airplanes. He gives a Cd total wetted area of .004 for P-51, .005 for the Bonanza, and .009 for the Cessna 170. For a Cd wingarea, he gives .017 for the P-51, .016 for the Bonanza, and .029 for the C-170. I suspect the Cd wet for the L235/320 should be somewhere between .004 and .005... and was looking for some confirmation. Terrence L235/320 N211AL ----- Original Message ----- From: "bob mackey" To: Sent: Monday, October 01, 2007 05:43 PM Subject: [LML] Drag coefficient > > I can't separate drag coefficient and area, because I haven't measured > the area, but we don't really need to. The equivalent (total) drag area > is: > > C*A = Drag / ((rho*v^2)/2) = 0.343 m^2 = 3.7 ft^2 > > Which is quite a bit greater than the ~1.6 that Paul Lipps sees in cruise. > I'll take that to mean that the prop/engine drag is about 2.1 ft^2 > equivalent drag area, assuming his airframe and mine are otherwise > similar. >