X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Thu, 11 Oct 2007 21:33:19 -0400 Message-ID: X-Original-Return-Path: Received: from imo-m26.mx.aol.com ([64.12.137.7] verified) by logan.com (CommuniGate Pro SMTP 5.1.12) with ESMTP id 2381827 for lml@lancaironline.net; Thu, 11 Oct 2007 14:48:52 -0400 Received-SPF: pass receiver=logan.com; client-ip=64.12.137.7; envelope-from=Sky2high@aol.com Received: from Sky2high@aol.com by imo-m26.mx.aol.com (mail_out_v38_r9.3.) id q.c70.1bcbd292 (30737) for ; Thu, 11 Oct 2007 14:48:14 -0400 (EDT) From: Sky2high@aol.com X-Original-Message-ID: X-Original-Date: Thu, 11 Oct 2007 14:48:13 EDT Subject: Re: [LML] spry shocks X-Original-To: lml@lancaironline.net MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="-----------------------------1192128493" X-Mailer: AOL 9.0 VR sub 165 X-Spam-Flag: NO -------------------------------1192128493 Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit In a message dated 10/11/2007 12:37:13 P.M. Central Daylight Time, genemartin@enid.com writes: On figuring main wheel weights for ordering spry shocks. I have my empty weights and can figure cg's but how do you get to main wheel weights from there without scales? narm*nwt + 2*Marm*Mwt = Moment nwt + 2*Mwt = Weight Moment/Weight = CG Record your cruise speed in furlongs per fortnight. Where, with the longerons level: CG = center of gravity measured from reference point (BL0, usually the aft side of the firewall). arm = measure point - BL0 n = center of nose wheel axle M = center of main gear axle (Note, for this example it is ok to assume the weight is equally distributed between the mains) Let A = the absolute distance (narm - Marm) Let B = the absolute distance (Marm - Harm) where Harm is the BL distance of the Horizontal Stab main Spar from the firewall. With a support below the tail, stack known weights (taken from the local exercise gym) on a cushion above the H-Stab Spar nearest to the vertical stab. When the nose wheel just begins to lift off the ground, record the weight as Hwt. This is an approximate balancing weight (about 150 lbs) because the longeron will not be level unless the mains are raised somewhat on blocks. Hwt * B = nwt * A or nwt = (Hwt*B)/A Mwt = (Weight - nwt)/2 (approximately) Check using the moment calculations. Ignore the cruise speed. Grayhawk PS Hint: empty, each main should statically be supporting about 430-450 lbs, depending. ************************************** See what's new at http://www.aol.com -------------------------------1192128493 Content-Type: text/html; charset="US-ASCII" Content-Transfer-Encoding: quoted-printable
In a message dated 10/11/2007 12:37:13 P.M. Central Daylight Time,=20 genemartin@enid.com writes:
<= FONT=20 style=3D"BACKGROUND-COLOR: transparent" face=3DArial color=3D#000000 size= =3D2>
On figuring main wheel weights for orderi= ng spry=20 shocks. I have my empty weights and can figure cg's but how do you get to=20= main=20 wheel weights from there without scales?
<= /DIV>
narm*nwt + 2*Marm*Mwt =3D Moment
nwt + 2*Mwt =3D Weight
Moment/Weight =3D CG
Record your cruise speed in furlongs per fortnight.
 
Where, with the longerons level:
CG =3D center of gravity measured from reference point (BL0, usual= ly=20 the aft side of the firewall).
arm =3D measure point - BL0
n =3D center of nose wheel axle
M =3D center of main gear axle (Note, for this example it is ok to= =20 assume the weight is equally distributed between the mains)
 
Let A =3D the absolute distance (narm - Marm)
Let B =3D the absolute distance (Marm - Harm) where Harm is the=20 BL distance of the Horizontal Stab main Spar from the firewall.
 
With a support below the tail, stack known weights (taken from the loca= l=20 exercise gym) on a cushion above the H-Stab Spar nearest to the vertical=20 stab.  When the nose wheel just begins to lift off the ground, rec= ord=20 the weight as Hwt.  This is an approximate balancing weight (about 150=20 lbs) because the longeron will not be level unless the mains are raised= =20 somewhat on blocks.
 
Hwt * B =3D nwt *  A   =20 or     nwt =3D (Hwt*B)/A
 
Mwt =3D (Weight - nwt)/2 (approximately)
 
Check using the moment calculations.
 
Ignore the cruise speed.
 
Grayhawk
 
PS Hint: empty, each main should statically be supporting about 430-450= =20 lbs, depending.
 
 
 
 
 




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