X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Mon, 08 Aug 2005 23:02:34 -0400 Message-ID: X-Original-Return-Path: Received: from imo-d03.mx.aol.com ([205.188.157.35] verified) by logan.com (CommuniGate Pro SMTP 4.3.7) with ESMTP id 641995 for lml@lancaironline.net; Mon, 08 Aug 2005 19:23:15 -0400 Received-SPF: pass receiver=logan.com; client-ip=205.188.157.35; envelope-from=REHBINC@aol.com Received: from REHBINC@aol.com by imo-d03.mx.aol.com (mail_out_v38_r4.1.) id q.147.4b0d1501 (3924) for ; Mon, 8 Aug 2005 19:22:26 -0400 (EDT) From: REHBINC@aol.com X-Original-Message-ID: <147.4b0d1501.30294333@aol.com> X-Original-Date: Mon, 8 Aug 2005 19:22:27 EDT Subject: Re: [LML] Re: Lower Cowl Air Temperature - Induction Air - Heater Air Temp X-Original-To: lml@lancaironline.net MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="-----------------------------1123543347" X-Mailer: 9.0 for Windows sub 5118 X-Spam-Flag: NO -------------------------------1123543347 Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit In a message dated 8/8/2005 5:07:53 PM Eastern Standard Time, Sky2high@aol.com writes: 3. Assuming all of the fuel can still be vaporized and combusted, it is prefferable to vaporize all of the fuel in the cylinder. The density of Gasoline is about 700 Kg/cm (kilograms per cubic meter) in the liquid phase and about 3.5 kg/cm in the vapor phase. Using the 70 deg. F change in air temperature given by Gary for vaporization temperature drop of the air and the ideal gas equation and assuming intitial air temperature of 350 Kelvin and a 14 to 1 air fuel ratio, we get the following equations: Specific volume liquid fuel mixture = (1 / 700 + 14 / 0.968) / 15 = 0.9643 cm/kg Specific volume gaseous fuel mixture = ( 1 / 3.5 + 14 / 1.092) / 15 = 0.8714 cm/kg Thus, 10.7 % more fuel mixture will fit into the cylinder if the fuel is in liquid form. Ahem, After glancing at what I wrote in Scott's reply, it would appear that a little self induced flaming is in order. Clearly, .8714 cm/kg is denser than .9643 cm/kg so the fully vaporized manifold mixture would increase the cylinder charge. I'm sorry for disagreeing with you Gary. Probably the result of a Monday morning haze. I still challenge anyone to get it all vaporized before the valve without adding a really large heater or a really large runner! Rob -------------------------------1123543347 Content-Type: text/html; charset="US-ASCII" Content-Transfer-Encoding: quoted-printable
In a message dated 8/8/2005 5:07:53 PM Eastern Standard Time, Sky2high@= aol.com writes:
3. Assuming all of the fuel can still be va= porized and combusted, it is prefferable to vaporize all of the fuel in the=20= cylinder. The density of Gasoline is about 700 Kg/cm (kilograms per cubic me= ter) in the liquid phase and about 3.5 kg/cm in the vapor phase. Using the 7= 0 deg. F change in air temperature given by Gary for vaporization tempe= rature drop of the air and the ideal gas equation and assuming intitial air=20= temperature of 350 Kelvin and a 14 to 1 air fuel ratio, we get the following= equations:
 
Specific volume liquid fuel mixture =3D&nbs= p; (1 / 700 + 14 / 0.968) / 15 =3D 0.9643 cm/kg
 
Specific volume gaseous fuel mixture = =3D ( 1 / 3.5 + 14 / 1.092) / 15 =3D 0.8714 cm/kg
 
Thus, 10.7 % more fuel mixture will fit int= o the cylinder if the fuel is in liquid form.
Ahem,
 
After glancing at what I wrote in Scott's reply, it would appear that a= little self induced flaming is in order. Clearly, .8714 cm/kg is denser tha= n .9643 cm/kg so the fully vaporized manifold mixture would increase the cyl= inder charge. I'm sorry for disagreeing with you Gary. Probably the result o= f a Monday morning haze.
 
I still challenge anyone to get it all vaporized before the valve witho= ut adding a really large heater or a really large runner!
 
Rob
-------------------------------1123543347--