Return-Path: Sender: "Marvin Kaye" To: lml@lancaironline.net Date: Tue, 18 Jan 2005 18:55:01 -0500 Message-ID: X-Original-Return-Path: Received: from [208.57.0.48] (HELO mgci.com) by logan.com (CommuniGate Pro SMTP 4.2.8) with SMTP id 612300 for lml@lancaironline.net; Tue, 18 Jan 2005 17:56:55 -0500 Received-SPF: none receiver=logan.com; client-ip=208.57.0.48; envelope-from=woodruff@swefco.com Received: (qmail 1934 invoked by uid 0); 18 Jan 2005 22:56:30 -0000 Received: from unknown (HELO ?192.168.0.2?) (66.18.129.84) by mgci.com with SMTP; 18 Jan 2005 22:56:30 -0000 User-Agent: Microsoft-Entourage/10.1.4.030702.0 X-Original-Date: Tue, 18 Jan 2005 14:56:23 -0800 Subject: Re: [LML] Re: Approach control From: Hal Woodruff X-Original-To: Lancair Mailing List X-Original-Message-ID: In-Reply-To: Mime-version: 1.0 Content-type: text/plain; charset="US-ASCII" Content-transfer-encoding: 7bit > one kilometer correspond to the 1/40.000th of the length of the equateur; > what is the statute mile corresponding to ?? Now, that's really handy to know. I'm planning a flight from Chino to Sedonna and it works out to be 0.01362 equators. I can do that in about 1.25 hours so that should make my speed... say about 0.010893 equators/hour. Now we're cookin' with gas. I suppose it would be easier and more meaningful to relate this as 10.9 meq/hr (meq - mili equators). Now if someone would hand me a calculator I need to compute the weight and balance... Let's see, the gross weight is 8.09587 x10^-7 z smu. (z smu = zepto solar-mass-units). Even with my wife's extra bag I should be under that. :) Hal Woodruff