Return-Path: Sender: (Marvin Kaye) To: lml Date: Fri, 02 May 2003 10:13:29 -0400 Message-ID: X-Original-Return-Path: Received: from www.dynacomm.ws ([198.22.63.66] verified) by logan.com (CommuniGate Pro SMTP 4.1b4) with ESMTP id 2330689 for lml@lancaironline.net; Fri, 02 May 2003 09:35:26 -0400 Received: from dynacomm.ws (adsl-66-72-177-114.dsl.sfldmi.ameritech.net [66.72.177.114]) by www.dynacomm.ws (8.10.2/8.10.2) with ESMTP id h42DZMi13891; Fri, 2 May 2003 09:35:22 -0400 X-Original-Date: Fri, 2 May 2003 09:35:17 -0400 Subject: Re: SUN 100 & Suffolk 100 Distance Content-Type: text/plain; charset=ISO-8859-1; format=flowed Mime-Version: 1.0 (Apple Message framework v552) X-Original-Cc: Scott Krueger , Ric Argente X-Original-To: "Lancair Mailing List" From: "Lorn H. Olsen" In-Reply-To: X-Original-Message-Id: Content-Transfer-Encoding: quoted-printable X-Mailer: Apple Mail (2.552) > From: Sky2high@aol.com > Date: Tue Mar 18, 2003 7:26:35 PM America/Detroit > > Feathers, et al: > > When one studies the SUN 100 course, it can be shown that ... 360 high=20= > speed turning degrees. > > Using Fig 2.29 (Constant Altitude, Steady Turn Performance) in=20 > "Aerodynamics for Naval Aviators" (NAVWEPS 00-80T-80) on can find that=20= > at 200 KTAS and a 60 degree banked turn, the radius is 2000 feet.=A0=20= > Thus, Pi x D =3D 12566 feet or 2.07 Nautical Miles. > > The turning radius for 200 KTAS, 30 degrees is about 6000 feet or 3=20 > times that of a 60 degree turn.=A0 Thus, taking turns at 30 degrees=20 > would add 6.2 NM to the course. > > Grayhawk > N92EX Grayhawk & Grease, I finally thought that I would do the calculations in great detail for=20= the Sun 100 Race. I used 7 points to calculate the distance. They were: 1) 500 ft from the touchdown end of runway 9 2) 500 ft past the end of runway 9 3) the SE GPS coordinates of the course 4) the SW GPS coordinates of the course 5) a point 1/4 nm W of the touchdown end of runway 9 6) the starting point The total distance came out to be 77.1 nm. Being the course is listed=20 at 82 nm, it looks like 4.9 nm was added to the course length or about=20= 5 nm. To verify this distance, I talked the Jerry Agular(sp) at Aircraft=20 Spruce(AC). Jerry is in charge of the course. I had Jerry explain why the course was listed as 82 nm. His response=20 was that it had been listed at 82 nm since before there were GPSs or=20 recorded history. He said that a few years ago the GPS coordinates were=20= taken on the ground. The coordinates seemed to confirm that with turns=20= the course was about 82 nm. The exact distance of the Suffolk 100 is 87.5 nm. If we add about 5 nm=20= to that we get 92 nm. We have listed on the Suffolk 100 web page that=20 the course is 93 nm. The calculated speed differential caused by this=20 one mile distance would be 92/93*200 =3D 2.2 kts. In other words, we=20 would be showing higher speeds of about 2.2 kts when compared to the=20 Sun 100 race. I hate to recommend it but i think that we should set the Suffolk 100=20 course distance at 92 nm. With this setting our speeds will compare=20 directly with the Sun 100 speeds. Other opinions are welcome. -- Lorn H. 'Feathers' Olsen, MAA, DynaComm, Corp. 248-478-4301, mailto:lorn@dynacomm.ws LNC2, O-320-D1F, N31161, Y47, SE Michigan=