Return-Path: Received: from portal.udlp.com ([207.109.1.80]) by truman.olsusa.com (Post.Office MTA v3.5.1 release 219 ID# 0-52269U2500L250S0V35) with ESMTP id com for ; Fri, 15 Jan 1999 22:11:56 -0500 Received: from portal.udlp.com (root@localhost) by portal.udlp.com with ESMTP id VAA10630 for ; Fri, 15 Jan 1999 21:13:23 -0600 (CST) Received: from ccmail.udlp.com ([128.254.66.12]) by portal.udlp.com with ESMTP id VAA10622 for ; Fri, 15 Jan 1999 21:13:22 -0600 (CST) Received: from ccMail by ccmail.udlp.com (IMA Internet Exchange 3.11) id 001EB39E; Fri, 15 Jan 1999 21:15:04 -0600 From: CHRISTOPHER_ZAVATSON@udlp.com Date: Fri, 15 Jan 1999 19:05:24 -0600 Message-ID: <001EB39E.C21254@udlp.com> Subject: Props, CS vs fixed pitch To: Lancair.list@olsusa.com X-Mailing-List: lancair.list@olsusa.com Mime-Version: 1.0 <<<<<<<<<<<<<<<<--->>>>>>>>>>>>>>>> << Lancair Builders' Mail List >> <<<<<<<<<<<<<<<<--->>>>>>>>>>>>>>>> >> >>> Just for reference, with a wooden, fixed pitch prop, I could get no more than about 2350 RPM for a sealevel takeoff and takeoff was a bit on the anemic side, to say the least. With the CS unit, I always get 2650-2700 RPM and the takeoffs are now quite sprightly affairs. Do the numbers; that's better than a 10% increase in takeoff horsepower (HP = T x RPM / K [K is a constant around 5200 for these regimes]). Nearly all of it is "excess power" needed to climb, which relates to better takeoff performance. Cheers, Dan Schaefer <<<< An addition to Dan Schaefer's response to Sven (SE-XOP) regarding props. The constant mentioned in the HP = T x rpm / k is fallout from the unit conversions required: hp = 550 ftlb/s T = ftlb rpm = (2*pi rad/s)/(60s/min) put it all together and you get: HP [550 ftlb/s] = T [ftlb] x rpm [(2*pi rad/s)/(60s/min)] HP = T x rpm /(550 ftlb/s x (60s/min)/(2*pi rad/s)) HP = T x rpm / 5252 With a CS prop, in addition to the engine putting out more horse power at the higher take off rpm, more of the prop blade is flying and providing thrust. A fixed pitch cruise prop can have a substantial portion of the blade in a stalled condition until sufficient forward velocity is obtained. If the pitch is too steep, enough of the blade can be stalled such that the aircraft can't accelerate at all. In this case all of the horse power being generated is going into stirring a lot of air and providing no thrust. Dan, your % thrust increase was probably much higher than your % power increase. CS all the way. Chris Zavatson N91CZ