Return-Path: Received: from pop3.olsusa.com ([63.150.212.2] verified) by logan.com (CommuniGate Pro SMTP 3.5b3) with ESMTP id 857851 for rob@logan.com; Mon, 27 Aug 2001 16:21:47 -0400 Received: from imo-d04.mx.aol.com ([205.188.157.36]) by pop3.olsusa.com (Post.Office MTA v3.5.3 release 223 ID# 0-71866U8000L800S0V35) with ESMTP id com for ; Mon, 27 Aug 2001 16:04:40 -0400 Received: from Epijk@aol.com by imo-d04.mx.aol.com (mail_out_v31_r1.4.) id k.d3.19df99d2 (3984) for ; Mon, 27 Aug 2001 16:15:13 -0400 (EDT) From: Epijk@aol.com Message-ID: Date: Mon, 27 Aug 2001 16:15:12 EDT Subject: Re: L/D Max To: lancair.list@olsusa.com MIME-Version: 1.0 Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit X-Mailing-List: lancair.list@olsusa.com Reply-To: lancair.list@olsusa.com <<<<<<<<<<<<<<<<--->>>>>>>>>>>>>>>> << Lancair Builders' Mail List >> <<<<<<<<<<<<<<<<--->>>>>>>>>>>>>>>> >> In a message dated 8/27/2001 1:08:53 PM Pacific Daylight Time, marvkaye@olsusa.com writes: << Speed for Longest Endurance= Speed for Max L/D Divided by 1.316 >> OK, 1.316 is the fourth root of 3 (square root of the square root of 3), but what is the derivation of that equation?? (When I see the answer, I'll probably know for sure what a dump question that was, but I don't immediately see the relationship. Thanks.) Jack Kane >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> LML website: http://www.olsusa.com/mkaye/maillist.html LML Builders' Bookstore: http://www.buildersbooks.com/lancair Please send your photos and drawings to marvkaye@olsusa.com. >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>