Return-Path: Received: from relay04.roc.ny.frontiernet.net ([66.133.131.37] verified) by logan.com (CommuniGate Pro SMTP 4.1.8) with ESMTP id 3050277 for flyrotary@lancaironline.net; Sat, 28 Feb 2004 21:07:18 -0500 Received: (qmail 21822 invoked from network); 29 Feb 2004 02:07:17 -0000 Received: from unknown (HELO frontiernet.net) ([170.215.99.215]) (envelope-sender ) by relay04.roc.ny.frontiernet.net (FrontierMTA 2.3.6) with SMTP for ; 29 Feb 2004 02:07:17 -0000 Message-ID: <4041493F.44ACB36D@frontiernet.net> Date: Sat, 28 Feb 2004 20:06:55 -0600 From: Jim Sower X-Mailer: Mozilla 4.77 [en] (Win98; U) X-Accept-Language: en MIME-Version: 1.0 To: Rotary motors in aircraft Subject: Re: [FlyRotary] Re: FW: [VAF Mailing List] Engine Choice References: Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit <... A wind milling prop DOES have hugh drag compared to a stopped one ...> I know a wind milling prop (prop turning engine) has more drag than a stopped prop (frozen engine or not enough airspeed to overcome engine compression). This guy specified a freewheeling prop (sprag clutch that is in the overrunning mode). There is no resistance at all to the prop and the only "work" the slipstream has to do is overcome the negligible sprag clutch free wheeling friction. Contrast that with the force required to overcome engine compression, or that required to try as hard as it can to overcome compression and not quite be able to do it. I can't argue with your experience, but I had always understood that a frozen prop had less drag than a prop wind milling the engine, but that the difference was not significant. A freewheeling prop is waaaay different from a wind milling prop. Like if you have a sprag clutch and turn up the engine to high rpm and then shut it down, the engine stops immediately but the prop will keep spinning for a couple of minutes. <... When you think wind milling drag ... think prop circle area, not just the blades cross section themselves. Square yards of drag, not square ft ...> I don't think that's exactly the way it works quantitatively. Maybe Marc can help. Oooops! Marc is not on this list. As I read it .... Jim S.