X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from imr-ma04.mx.aol.com ([64.12.206.42] verified) by logan.com (CommuniGate Pro SMTP 5.4.6) with ESMTP id 5644124 for flyrotary@lancaironline.net; Mon, 09 Jul 2012 12:43:11 -0400 Received-SPF: pass receiver=logan.com; client-ip=64.12.206.42; envelope-from=bktrub@aol.com Received: from mtaomg-ma01.r1000.mx.aol.com (mtaomg-ma01.r1000.mx.aol.com [172.29.41.8]) by imr-ma04.mx.aol.com (8.14.1/8.14.1) with ESMTP id q69GgUf1008802 for ; Mon, 9 Jul 2012 12:42:30 -0400 Received: from core-dub005c.r1000.mail.aol.com (core-dub005.r1000.mail.aol.com [172.29.164.82]) by mtaomg-ma01.r1000.mx.aol.com (OMAG/Core Interface) with ESMTP id 79D50E000086 for ; Mon, 9 Jul 2012 12:42:30 -0400 (EDT) To: flyrotary@lancaironline.net Subject: On the step X-MB-Message-Source: WebUI X-MB-Message-Type: User MIME-Version: 1.0 From: bktrub@aol.com Content-Type: multipart/alternative; boundary="--------MB_8CF2C08F744B2E2_1CC0_1252D3_webmail-d076.sysops.aol.com" X-Mailer: AOL Webmail 36542-STANDARD Received: from 23.25.136.85 by webmail-d076.sysops.aol.com (205.188.181.102) with HTTP (WebMailUI); Mon, 09 Jul 2012 12:42:30 -0400 Message-Id: <8CF2C08F73B2D56-1CC0-539B4@webmail-d076.sysops.aol.com> X-Originating-IP: [23.25.136.85] Date: Mon, 9 Jul 2012 12:42:30 -0400 (EDT) x-aol-global-disposition: G DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=mx.aol.com; s=20110426; t=1341852150; bh=G1qF0RNXJkvqsDoxB4wUeWPWMQPVbjEqWIf6AvbaY3o=; h=From:To:Subject:Message-Id:Date:MIME-Version:Content-Type; b=sapetbDQcdhfZAkbJia6OU2N4iRZ0tETPjYnmb2k8Rf+psFQsEfZWd3lEx1tTk7Je cSCVLP9FwQ56IJvO5frH9WZV8WY7AS6wUg46x0lFPlEXzZC74mJzRrJzPSB3DoTnc4 1HWTfuSfKOcmxVPmAHGyWDc+h8wO1zihmFooGgRw= X-AOL-SCOLL-SCORE: 0:2:358279168:93952408 X-AOL-SCOLL-URL_COUNT: 0 x-aol-sid: 3039ac1d29084ffb09f63397 This is a multi-part message in MIME format. ----------MB_8CF2C08F744B2E2_1CC0_1252D3_webmail-d076.sysops.aol.com Content-Transfer-Encoding: quoted-printable Content-Type: text/plain; charset="us-ascii" I commented on here recently about how I took a cross- country flight to Wa= lla Walla from Everett, Wa recently and was only seeing 140-150 mph cruise = at 11,500 feet. It got me to thinking- I was getting about 6200 rpm on the = engine which is 2175 at the prop. So, I'm a little overpropped/ underpowere= d.=20 So, there's the old chestnut about how you can get a few more knots from an= airplane in cruise if you go a little above your cruise altitude and then = descend to your cruise altitude, thereby getting "on the step" . Some pilot= s swear by this, others dismiss it. I have a theory- if I climb to a cruise= altitude and stay at full throttle while doing so, I will only get the eng= ine to run up to a certain RPM and therefore a certain hp will be achieved,= and no more and so the airplane will settle into an equilibrium at a certa= in speed- say at whatever hp/speed - 140 mph at 6200 rpm- lt's say x hp.=20 Now, If I were to descend to my cruise altitude in a shallow dive, I will b= e acheiving a higher rpm and hence horsepower, say 6800 rpm and horsepower = will be x + 9%x for a hp of 109% of the hp achieved at 6200 rpm, so I shoul= d be able to achieve and maintain a higher cruise speed if I descend to my= cruising altitude. ( I picked 9% arbitrarily for the sake of argument) . Anyone want to shoot me down on this one? This is just an theory, If I want to go faster first I have to clean up my = drag. My cooling scoop is effective, but obviously draggy. And It needs a f= lap on it. That's a project for this winter.=20 Brian Trubee ----------MB_8CF2C08F744B2E2_1CC0_1252D3_webmail-d076.sysops.aol.com Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii"
I commented on here recently about how I took a cross- countr= y flight to Walla Walla from Everett, Wa recently and was only seeing 140-1= 50 mph cruise at 11,500 feet. It got me to thinking- I was getting about 62= 00 rpm on the engine which is 2175 at the prop. So, I'm a little overproppe= d/ underpowered.
 
So, there's the old chestnut about how you can get a few more knots fr= om an airplane in cruise if you go a little above your cruise altitude and = then descend to your cruise altitude, thereby getting "on the step" . Some = pilots swear by this, others dismiss it. I have a theory- if I climb to a c= ruise altitude and stay at full throttle while doing so, I will only get th= e engine to run up to a certain RPM and therefore a certain hp will be achi= eved, and no more and so the airplane will settle into an equilibrium at a = certain speed- say at whatever hp/speed - 140 mph at 6200 rpm- lt's say x h= p.
 
Now, If I were to descend to my cruise altitude in a shallow dive, I w= ill be acheiving a higher rpm and hence horsepower, say 6800 rpm and horsep= ower will be x + 9%x for a hp of 109% of the hp achieved at 6200 rpm, so I = should be able to achieve and maintain a higher cruise  speed if I des= cend to my cruising altitude. ( I picked 9% arbitrarily for the sake of arg= ument) .
 
Anyone want to shoot me down on this one?
 
This is just an theory, If I want to go faster first I have to clean u= p my drag. My cooling scoop is effective, but obviously draggy. And It need= s a flap on it. That's a project for this winter.
 
Brian Trubee
----------MB_8CF2C08F744B2E2_1CC0_1252D3_webmail-d076.sysops.aol.com--