X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from fed1rmmtao101.cox.net ([68.230.241.45] verified) by logan.com (CommuniGate Pro SMTP 5.2c2) with ESMTP id 2470426 for flyrotary@lancaironline.net; Tue, 13 Nov 2007 15:26:27 -0500 Received-SPF: none receiver=logan.com; client-ip=68.230.241.45; envelope-from=alventures@cox.net Received: from fed1rmimpo02.cox.net ([70.169.32.72]) by fed1rmmtao101.cox.net (InterMail vM.7.08.02.01 201-2186-121-102-20070209) with ESMTP id <20071113202549.GYQY28469.fed1rmmtao101.cox.net@fed1rmimpo02.cox.net> for ; Tue, 13 Nov 2007 15:25:49 -0500 Received: from BigAl ([72.192.143.193]) by fed1rmimpo02.cox.net with bizsmtp id CLRo1Y0054AaN600000000; Tue, 13 Nov 2007 15:25:48 -0500 From: "Al Gietzen" To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] Thick vs Thin was : Diffuser Configuration Comparison Date: Tue, 13 Nov 2007 12:26:06 -0800 Message-ID: <000701c82633$6b8401a0$6401a8c0@BigAl> MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6626 Importance: Normal X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.3198 In-Reply-To: Ron; I'm with you all the way until you get to: " Then, because heat transfer = and drag scale with velocity squared," I'm aware that the heat transfer is not linear with velocity, but how = does it go as go as the square? I have a ROT that a 16 fin/in rad with 1/2" tube spacing should be 2 = 3/4" thick; and I'm sticking to it:-) Oh; I have another ROT; the diffuser = area ratio should be in the range of 4 - 6. Al G Subject: [FlyRotary] Thick vs Thin was : Diffuser Configuration = Comparison Assume you have two radiators: 1) Radiator 1 is twice the frontal area of Radiator 2 2) Same wetted fin area and fin spacing, so Radiator 2 is twice as thick as Radiator 1. 3) Same air inlet with same mass flow rate 4) Different diffusers, but both have no flow separation and perfectly uniform flow arrives at the radiator face. 5) Both radiators have the same average skin friction coefficient and average heat transfer coefficient in the boundary layers that develop across the fins (this is a small stretch and could be refined, but it is not going to change the trends in this example). Then, because heat transfer and drag scale with velocity squared, and velocity is twice as high for the thick radiator, and the thick radiator would have four times the heat transfer, but also four times the drag. There is always a tradeoff between heat transfer and drag. That is my take on the situation. Ron -- Homepage: http://www.flyrotary.com/ Archive and UnSub: http://mail.lancaironline.net:81/lists/flyrotary/List.html