Return-Path: Received: from border.rfgonline.com ([65.171.123.242] verified) by logan.com (CommuniGate Pro SMTP 4.1.5) with ESMTP-TLS id 2644495 for flyrotary@lancaironline.net; Mon, 20 Oct 2003 23:10:03 -0400 Received: (qmail 3408 invoked from network); 21 Oct 2003 03:17:11 -0000 Received: from unknown (HELO EXCHANGE.rfgonline.com) (192.168.150.101) by 192.168.150.1 with SMTP; 21 Oct 2003 03:17:11 -0000 X-MimeOLE: Produced By Microsoft Exchange V6.0.6249.0 content-class: urn:content-classes:message MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Subject: RE: [FlyRotary] Cooling Model Enhancement Date: Mon, 20 Oct 2003 23:10:02 -0400 Message-ID: <0B27ED95697C4D4CBC82D79E790FE567086FAA@exchange.rfgonline.com> X-MS-Has-Attach: X-MS-TNEF-Correlator: Thread-Topic: [FlyRotary] Cooling Model Enhancement Thread-Index: AcOXfXgwVL3+hn9vQP+HPVft8vbWMwAAI96A From: "Robinson, Chad" To: "Rotary motors in aircraft" Ed, are these calculated or measured numbers? If calculated, what's the = formula being used? This should normally be a tricky business. Cooling/heating formulae = normally involve the specific heat and mass of the substance being = cooled, the amount of heat transferred, etc. One common formula is: heat transferred =3D mass * deltaT * specific heat (1 for water) So yeah, this seems odd. The bigger the deltaT (in this case, difference = between air and radiator temperature) the more heat you can transfer. There are a bunch of these at: http://www.fordhamprep.com/gcurran/sho/sho/lessons/lesson210.htm But a complete formula is complex because it depends on radiator = configuration, efficiency, etc. I found a bunch of auto = radiator-specific formulae at: http://www.unb.ca/che/Undergrad/proposed/auto.pdf but then you're on your own. Or you could ask one of the ACRE guys. =3D) > -----Original Message----- > From: Ed Anderson [mailto:eanderson@carolina.rr.com] > Sent: Monday, October 20, 2003 10:46 PM > To: Rotary motors in aircraft > Subject: [FlyRotary] Cooling Model Enhancement >=20 >=20 > I finally found a math model that provides the rise in=20 > temperature as it > goes through a radiator. The model indicates that for the=20 > two evaporator > cores that the air temp should rise between 35F and 38F for=20 > 161 HP at 120 > MPH burning 15 GPH. Less of a rise if less BTU are being generated. >=20 > Here is what the temp rise model gives (all temps in farenheit): >=20 > OAT Delta T Exit Radiator >=20 > 0 34.9 34.9 >=20 > 30 35.59 65.59 >=20 > 60 36.15 96.15 >=20 > 90 36.02 126.02 >=20 > 120 37.48 157.48 >=20 > I guess I am surprised to find that the delta T is decreasing with > decreasing OAT. The only way I can rationalize the lower=20 > delta T at the > lower temps still removing the same amount of heat is that=20 > the cold air is > denser and therefore the mass flow is greater and that=20 > accounts for carring > away the same amount of heat with a lower Delta T. Would any of your > thermodynamic folks comment on this? >=20 > In any case, it appears that some of Todd's delta T figures=20 > fall in this > ball park, so this model may not be too far off. >=20 >=20 > Ed Anderson > RV-6A N494BW Rotary Powered > Matthews, NC > eanderson@carolina.rr.com >=20 >=20 >=20 > >> Homepage: http://www.flyrotary.com/ > >> Archive: http://lancaironline.net/lists/flyrotary/List.html >=20