Return-Path: <13brv3@bellsouth.net> Received: from imf17aec.mail.bellsouth.net ([205.152.59.65] verified) by logan.com (CommuniGate Pro SMTP 4.1) with ESMTP id 2513660 for flyrotary@lancaironline.net; Wed, 06 Aug 2003 18:09:29 -0400 Received: from rad ([68.212.1.179]) by imf17aec.mail.bellsouth.net (InterMail vM.5.01.05.27 201-253-122-126-127-20021220) with ESMTP id <20030806220929.GTDH6813.imf17aec.mail.bellsouth.net@rad> for ; Wed, 6 Aug 2003 18:09:29 -0400 From: "Russell Duffy" <13brv3@bellsouth.net> To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] Legal Gross Weight Date: Wed, 6 Aug 2003 17:09:28 -0500 Message-ID: <000001c35c67$67fd8280$0201a8c0@rad> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0001_01C35C3D.7F277A80" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.4510 Importance: Normal In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1165 This is a multi-part message in MIME format. ------=_NextPart_000_0001_01C35C3D.7F277A80 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit Rusty, FWIW I agree in general with the comments about "legal" gross weight. My RV's design gross weight is designated by Van as 1650 lbs. however, the tail plate and my aircraft airworthiness paperwork has its "legal" gross weight as 1800 lbs. Thanks to all who commented on this. Setting the weight high seems to be the consensus. Can I figure that 6 G's at 1100 lbs, is equal to 4.89 G's at 1350 lbs? Is it really that simple? Cheers, Rusty ------=_NextPart_000_0001_01C35C3D.7F277A80 Content-Type: text/html; charset="us-ascii" Content-Transfer-Encoding: quoted-printable Message

Rusty, FWIW  I agree in general with the comments = about=20 "legal" gross weight.  My RV's design gross weight is designated by = Van as=20 1650 lbs. however, the tail plate and my aircraft airworthiness = paperwork has=20 its "legal" gross weight as 1800 lbs. 

 
Thanks = to all who=20 commented on this.  Setting the weight high seems to be the=20 consensus. 
 
Can I = figure that 6=20 G's at 1100 lbs, is equal to 4.89 G's at 1350 lbs?  Is it = really=20 that simple? 
 
Cheers,
Rusty
 
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