X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Sun, 08 Aug 2010 19:46:01 -0400 Message-ID: X-Original-Return-Path: Received: from web36903.mail.mud.yahoo.com ([209.191.85.71] verified) by logan.com (CommuniGate Pro SMTP 5.3.8) with SMTP id 4422507 for lml@lancaironline.net; Sat, 07 Aug 2010 22:14:49 -0400 Received-SPF: none receiver=logan.com; client-ip=209.191.85.71; envelope-from=chris_zavatson@yahoo.com Received: (qmail 4559 invoked by uid 60001); 8 Aug 2010 02:14:12 -0000 DomainKey-Signature:a=rsa-sha1; q=dns; c=nofws; s=s1024; d=yahoo.com; h=Message-ID:X-YMail-OSG:Received:X-Mailer:References:Date:From:Subject:To:In-Reply-To:MIME-Version:Content-Type; b=lk5BmhCm4WVT5V3BBiw10yCBT5O3gmsqNxUm8p0lNH+8skkOmUEh/R3+mluMMbtVe8LrUH3xgPTOkkpt4t3mvDE8ZuTKGCEnkHi64gYngE3SNk8GRzGJohLg83annxUuCov/+97Ebp3H6JUg5nDe4hUBNJPKanfgZ1YoIZJiMpA=; X-Original-Message-ID: <540449.3834.qm@web36903.mail.mud.yahoo.com> X-YMail-OSG: btiiM5gVM1mwm_UxAUCPnT09gZDekoAwdUAd9yYv2fLduoo NAnrdVmJe3O9bq4Fh3edTu_JBjRp6kJIUHzxFkREJGsh03vG.jQDGrdIie5u tfECOmRzZ.e9krrpMhkKJg.VBWMKHVR8i6w11zysI7DWtGtaLLTdEPplWFR. uL0qlPLj3Mg5ac21TfiXO2NVYRvCMcymcs2xG1lHn59DceSlbLI2OvY1LjX. l1kKRh5D2Y0Pgkf4wRCPF1KHfcZkysovb_Ow3KK55CV2TSxX9hWtdAi8Jo4p Q5pP3HZWXhiWoGlf3ZcBbBQacT5CHgGE6n5eMcKtbtPZcHQFLGiXRoeSow5U MJexyVFHi.C6YHHHGUoNCZTWX Received: from [76.246.44.81] by web36903.mail.mud.yahoo.com via HTTP; Sat, 07 Aug 2010 19:14:12 PDT X-Mailer: YahooMailRC/459 YahooMailWebService/0.8.105.279950 References: X-Original-Date: Sat, 7 Aug 2010 19:14:12 -0700 (PDT) From: Chris Zavatson Subject: Re: [LML] Re: flap coupling X-Original-To: Lancair Mailing List In-Reply-To: MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="0-1422824441-1281233652=:3834" --0-1422824441-1281233652=:3834 Content-Type: text/plain; charset=iso-8859-1 Content-Transfer-Encoding: quoted-printable The MKII tail is a little different.=A0=A0Push rod forces are zero for all = trimmed =0Aconditions.=0A=0AChris Zavatson=A0=A0=A0 =0AN91CZ=A0=A0=A0 =0A36= 0std=0Awww.N91CZ.com=0A=0A=A0=0A=0A=0A=0A________________________________= =0AFrom: Wolfgang =0ATo: lml@lancaironline.net=0ASent: = Fri, August 6, 2010 10:06:44 PM=0ASubject: [LML] Re: flap coupling=0A=0A=0A= I have taken elevator pushrod force measurements and was surprised.=0AEleva= tor pushrod forces to stick forces are about 6.5 to 1=0AThe trim system, wh= en dialed in, provides these forces.=0A=A0=0AAt=A0190 imph and -7=BA flaps,= there is a 60lb forward force.=0AAt 80 imph and 10=BA flaps, there is abou= t zero force.=0AAt 80 imph and 20=BA flaps, there is a slight (-1lb)=A0rear= ward force.=0A=A0=0AThese numbers are with the horizontal stabilizer built = at -1.2=BA=0A- - - plans range is -0.5=BA to -1.0=BA=0A=A0=0AAn=A0input fro= m the flap bellcrank of about 20-40 lb at -7=BA would be good,=0A=A0taperin= g down to zero lbs at 10=BA flaps=0A=A0=0AA horizontal stabilizer built at = -0.5=BA would, of course, change these numbers.=0A=A0=0AComments ?=0A=A0=0A= Wolfgang=0A=0A=0A --0-1422824441-1281233652=:3834 Content-Type: text/html; charset=iso-8859-1 Content-Transfer-Encoding: quoted-printable
The MKII tail is a little different.  Push rod forces a= re zero for all trimmed conditions.
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Chris = Zavatson   
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N91CZ   
=0A<= DIV>360std
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=0AFrom: Wolfgang <Wolfgang@MiCom.net>
To: lml@lancaironline.net
Sent: Fri, August 6, 2010 10:06:44 PM
Subject: [LML] Re: flap coupling
<= BR>=0A=0A=0A
I have taken el= evator pushrod force measurements and was surprised.
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Elevator pushrod forces to stick forces are about= 6.5 to 1
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The trim system, = when dialed in, provides these forces.
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At = 190 imph and -7=BA flaps, there is a 60lb forward force.
=0AAt 80 imph and 10=BA flaps, there is about ze= ro force.
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At 80 imph and 20= =BA flaps, there is a slight (-1lb) rearward force.
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These numbers are with the horizontal stabilizer built at -1.2=BA=
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- - - plans range is -0.5= =BA to -1.0=BA
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 = ;
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An input from the flap bell= crank of about 20-40 lb at -7=BA would be good,
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 tapering down to zero lbs at 10=BA flaps<= /DIV>=0A
 
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A horizontal stabilizer built at -0.5=BA would, of cou= rse, change these numbers.
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Comments ?=0A
 
=0A
Wolfgang
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