|
Reply to Dan Schaefer:
No flames from me. Everything you said was correct, but I would like to elaborate on a couple of your points.
In your home, the function of a circuit breaker is *only* to protect the wiring, as you wrote. Your typical 20A circuit breaker will not protect your garbage disposal from burning up if something gets jammed in there, for example. That's why they have their own thermal circuit breakers (that little red button down there). In an industrial setting, thermal-magnetic circuit breakers are used to protect large motors, and the 'heaters' are sized to protect the motor in case of a locked rotor.
It's my belief that the circuit breaker (or fuse) feeding the hydraulic pump in the Lancair should be sized to protect the pump from burning up, in addition to protecting the wiring, I believe that it *is* possible.
I have the specifications right here for the Oildyne (now Parker) Model 108AA19-AL-3VT as used in my Lancair 235. Unfortunately, it doesn't list the locked-rotor current for the series-wound 12V DC motor. The chart in there says that the motor draws ~15 Amps at low pressure, and about 40 Amps at 1500 PSI. It's my vague recollection that the locked-rotor current for this motor is a little over 70 Amps, but I can't remember where I came up with that. So just now, I did the best I could to measure it by replacing the 40A Maxi-Fuse that I use to protect the pump/wiring with 12" of 18AWG stranded wire as a 'shunt'. From wire tables, the resistance of that piece of wire should be between .0055 and .0065 ohms, but I have no way to measure it. Using my Fluke 87-V, the 'peak inrush' (250 uS) across the 'shunt' was 0.90V, the 100ms peak was 0.50V, and the voltage while the gear was coming up was ~0.30V. In theory, the peak inrush should be the same as the locked-rotor current, since both are measured with the motor not rotating.
Using the 6.0 ohms per 1000' average, that works out to a peak inrush of 150 amps, a 100ms peak of 83 Amps, and a transition current of 50 Amps. My gut tells me that those readings are too high by a factor of two, so the resistance of my 'shunt' must be greater than I think it is (* maybe not. See addendum). The point still remains, though, that the current this motor will draw if something gets jammed in the gears is roughly three times 'normal'. Whatever protection device you choose should be sized to trip within a few seconds under those conditions.
(As a side note, while the inrush currents were the same in both directions, the motor drew only 2/3 the current with the gear coming 'down' as it did coming 'up'. And if anybody was wondering, after five gear cycles the piece of #18 AWG wire was warm to the touch, but not 'hot'.)
I'm attaching the time-current curves for a typical Klixon 7271 circuit breaker. Per their specifications, the Klixon may never trip at all with a 10% to 45% overload. With a 35 Amp breaker, that would mean the hydraulic pump could draw from 38.5 to 50.75 Amps without the breaker ever tripping. At a minimum, your wiring needs to be able to handle that. AWG #10 would be a minimum, I think. With a locked rotor and assuming the pump draws somewhere around 70 Amps (a 200% overload with a 35A breaker), the Klixon 7271 circuit breaker would trip anywhere between 8 and 80 seconds. It's my belief that either the pump itself or the wiring would burn up if the breaker took 80 seconds to trip. Data for other Klixon models can be found at: http://www.sensata.com/download/klixon-circuit-breaker-aircraft-catalog.pdf
Now looking at the Maxi-Fuse data at http://www.littelfuse.com/data/en/Data_Sheets/299.pdf, I find that a 35 Amp Maxi-Fuse will open on a 200% overload between 6 and 40 seconds (20 seconds, on average), substantially faster than a similarly rated circuit breaker. The 30 Amp Maxi-Fuse, if one chose to use that rating, would open in less than ten seconds with a locked rotor.
The point of all this is that we builders should have some idea what the hydraulic pump draws under what conditions, and the capabilities and limitations of whatever device we choose to protect it and the wiring. One advantage to using the Maxi-Fuse rather than the circuit breaker, is that it allows the builder to experiment and find the proper rating for his installation without having to rewire the panel.
*Addendum: In the link above, they listed the cold resistance of the 40A Maxi-Fuse as 1.42 milli-ohms. So I installed one of those as a shunt and re-did the test. I came up with similar (even higher) numbers than before: 211/126/54 Amps. I guess my 'gut feeling' was wrong. Now I'm going to have to buy a 200A shunt to verify all this. Nuts!
tripcurve-7270.gif
|
|