X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Thu, 16 Aug 2007 21:19:17 -0400 Message-ID: X-Original-Return-Path: Received: from imo-d22.mx.aol.com ([205.188.144.208] verified) by logan.com (CommuniGate Pro SMTP 5.1.11) with ESMTP id 2265269 for lml@lancaironline.net; Wed, 15 Aug 2007 20:45:11 -0400 Received-SPF: pass receiver=logan.com; client-ip=205.188.144.208; envelope-from=Sky2high@aol.com Received: from Sky2high@aol.com by imo-d22.mx.aol.com (mail_out_v38_r9.2.) id q.c84.185411d6 (14501) for ; Wed, 15 Aug 2007 20:44:30 -0400 (EDT) From: Sky2high@aol.com X-Original-Message-ID: X-Original-Date: Wed, 15 Aug 2007 20:44:29 EDT Subject: Re: [LML] Re: Apologies to the farmer's daughter X-Original-To: lml@lancaironline.net MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="-----------------------------1187225069" X-Mailer: 9.0 Security Edition for Windows sub 5373 X-Spam-Flag: NO -------------------------------1187225069 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Content-Language: en =20 In a message dated 8/15/2007 5:47:58 P.M. Central Daylight Time, =20 rtitsworth@mindspring.com writes: Gravitational acceleration is approx 32ft/sec^2 (drag-less freefall at the=20 Earth=E2=80=99s surface)=20 Doing some algebra to solve for the time to reach 25 fps results in: =20 (25/32)^.5 =3D 0.88 seconds=20 Doing some integral calculus (not shown) results in a distance traveled of=20 approx 7.5 feet=20 Thus, 25 f/s is about the impact speed from falling off the top step of an=20= 8=E2=80=99 step ladder=20 Be careful when cleaning your gutters out there J=20 Or another analogy (in case you haven;t fallen off the top of a 8=E2=80=99=20= step=20 ladder lately), terminal velocity from the top of a 34=E2=80=9D bar stool w= ould be=20 approximately 12.5 fps (note: 1/2 speed =3D 1/4 of the impact energy). Rick, =20 You have ignored the slowing effects of being outside a vacuum. =20 Furthermore, I have fallen off a standard barstool at 21C, dalt 1114 MSL, 6= 7% humidity. =20 It wasn't all that bad they tell me. Apparently, I was unconsciously loose= =20 when I hit the stop. This is not a suggestion on how to reduce the persona= l=20 effects of such a sudden deceleration as there isn't enough time available=20= to=20 reach the state of relaxation that I was in - either by meditation or, uh,=20 other means. I hear I bounced, thus reducing the impact because of the=20 rebound elasticity and the final plop was from a much lower AGL. Alas, if=20= only a=20 strain gauge had been attached so I could report actual data rather than th= ese=20 theoretical computations being tossed about. =20 Grayhawk ************************************** Get a sneak peek of the all-new AOL a= t=20 http://discover.aol.com/memed/aolcom30tour -------------------------------1187225069 Content-Type: text/html; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Content-Language: en
In a message dated 8/15/2007 5:47:58 P.M. Central Daylight Time,=20 rtitsworth@mindspring.com writes:
<= FONT=20 style=3D"BACKGROUND-COLOR: transparent" face=3DArial color=3D#000080 size= =3D2>

Gravitational=20 acceleration is approx 32ft/sec^2 (drag-less freefall at the Earth=E2=80= =99s=20 surface)

Doing some alge= bra to=20 solve for the time to reach 25 fps results in:  (25/32)^.5 =3D 0.88=20 seconds

Doing some inte= gral=20 calculus (not shown) results in a distance traveled of approx 7.5=20 feet

Thus, 25 f/s is= about=20 the impact speed from falling off the top step of an 8=E2=80=99 step=20 ladder

Be careful when= =20 cleaning your gutters out there J

 

Or another anal= ogy=20 (in case you haven;t fallen off the top of a 8=E2=80=99 step ladder lately= ), terminal=20 velocity from the top of a 34=E2=80=9D bar stool would be approximately 12= .5 fps=20 (note: 1/2 speed =3D 1/4 of t= he=20 impact energy).

Rick,
 
You have ignored the slowing effects of being outside a vacuum.&nb= sp;=20 Furthermore, I have fallen off a standard barstool at 21C, dalt 1114 MS= L,=20 67% humidity.  It wasn't all that bad they tell me.  Apparently, I= was=20 unconsciously loose when I hit the stop.  This is not a suggestion= on=20 how to reduce the personal effects of such a sudden deceleration as the= re=20 isn't enough time available to reach the state of relaxation that = I=20 was in - either by meditation or, uh, other means.  I hear I bounced, t= hus=20 reducing the impact because of the rebound elasticity and the final=20 plop was from a much lower AGL.  Alas, if only a strain gauge had=20= been=20 attached so I could report actual data rather than these theoretical=20 computations being tossed about.
 
Grayhawk




Get a sneak=20= peek of the all-new AOL.com.
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