X-Virus-Scanned: clean according to Sophos on Logan.com X-SpamCatcher-Score: 2 [X] Return-Path: Sender: To: lml@lancaironline.net Date: Mon, 19 Mar 2007 13:06:30 -0400 Message-ID: X-Original-Return-Path: Received: from imo-m24.mx.aol.com ([64.12.137.5] verified) by logan.com (CommuniGate Pro SMTP 5.1.7) with ESMTP id 1928187 for lml@lancaironline.net; Sun, 18 Mar 2007 18:55:34 -0400 Received-SPF: pass receiver=logan.com; client-ip=64.12.137.5; envelope-from=Sky2high@aol.com Received: from Sky2high@aol.com by imo-m24.mx.aol.com (mail_out_v38_r7.6.) id q.ca4.ba81f77 (43930) for ; Sun, 18 Mar 2007 18:54:38 -0400 (EDT) From: Sky2high@aol.com X-Original-Message-ID: X-Original-Date: Sun, 18 Mar 2007 18:54:37 EDT Subject: Re: [LML] Re: Wing Fuel Imbalance Question X-Original-To: lml@lancaironline.net MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="-----------------------------1174258477" X-Mailer: 9.0 Security Edition for Windows sub 5358 X-Spam-Flag: NO -------------------------------1174258477 Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit Mike, You will have to do the calculations for an ES and let us know the results. Consider an arbitrary aircraft that carries 25 gallons of fuel in each wing and that the fuel is located between BL50 and BL100 (50 to 100 inches from the centerline) and that the tank is of a constant shape. Then BL75 is the fuel tank CG and (75 inches x 25 gal x 6 lbs/gal) / 12 inches/foot = 937.5 as a lateral moment. Assuming the cabin width is 48", let's say a front seat person's CG is at BL18 or 1.5 feet 937.5/1.5 = 625 pounds (moment / arm = weight). If you can find a 625# person to sit on the empty wing side, you would be in balance as though the wing were full (although you may be over gross). A 220# person would be the equivalent of only about 9 gallons evenly spread thru the tank. Think about the wing taper and movement of the CG as the fuel is used - that is, remaining fuel weight is more towards the center of the aircraft and less of an imbalance. The imbalance will be less as you approach your destination. Scott Krueger AKA Grayhawk Lancair N92EX IO320 SB 89/96 Aurora, IL (KARR) Darwinian culling phrase: Watch This! ************************************** AOL now offers free email to everyone. Find out more about what's free from AOL at http://www.aol.com. -------------------------------1174258477 Content-Type: text/html; charset="US-ASCII" Content-Transfer-Encoding: quoted-printable

Mike,

You will have to do the calculations for an ES and let us know the resu= lts.=20 Consider an arbitrary aircraft that carries 25 gallons of fuel in each=20= wing=20 and that the fuel is located between BL50 and BL100 (50 to 100 inches from t= he=20 centerline) and that the tank is of a constant shape. Then=20= BL75=20 is the fuel tank CG and

(75 inches x 25 gal x 6 lbs/gal) / 12 inches/foot =3D 937.5 as a=20 lateral moment.

Assuming the cabin width is 48", let's say a front seat person's CG is=20= at=20 BL18 or 1.5 feet

937.5/1.5 =3D 625 pounds (moment / arm =3D weight).

If you can find a 625# person to sit on the empty wing side, you would=20= be=20 in balance as though the wing were full (although you may be over gross).

A 220# person would be the equivalent of only about 9 gallons even= ly=20 spread thru the tank.

Think about the wing taper and movement of the CG as the fuel= is=20 used - that is, remaining fuel weight is more towards the center o= f=20 the aircraft and less of an imbalance.

The imbalance will be less as you approach your destination.=20

Scott Krueger=20 AKA Grayhawk
Lancair N92EX IO320 SB 89/96
Aurora, IL=20 (KARR)

Darwinian culling phrase: Watch=20 This!

AOL now= offers free email to everyone. Find out more about what's free from AOL at= AOL.com.

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