Mailing List lml@lancaironline.net Message #35842
From: richard titsworth <rtitsworth@mindspring.com>
Sender: <marv@lancaironline.net>
Subject: RE: [LML] Re: Poor Man's Dyno
Date: Fri, 12 May 2006 17:12:08 -0400
To: <lml@lancaironline.net>

I believe both viewpoints of this discussion/thread have elements of correctness. 

If I understand it correctly, then the pictures and discussion below are an attempt to add some clarity.

 

Imagine two identical airplanes except they have different landing gear geometries – but they are the same and symmetrical at the ground (and identical weights).

 

For definition let’s call the left side the slant gear and let’s call the right side the vertical gear

 

 

 

 

By definition: Torque = Moment Arm X Force (perpendicular to the direction of rotation).

 

For all mention of “forces on the scales” below, I am assuming the scales have been zero’d with the aircraft not running (i.e. subtracting the tare weight of the aircraft).

 

So, lets get to work…

 

If you were attempting to measure torque using the slant gear aircraft, and were using the actual gear geometry as the basis for measuring the relevant forces and moment arm, then the scale would only indicate a portion (the vertical component) of the torque force. (ref: slant gear picture below).  Note, the Moment Arm is the slant distance from the axis of rotation to the contact spot on the scale

 

 

In this case, a geometric (trigonometry) correction factor must be applied to the force indicated on the scale.  The correction factor is the 1/cos of the gear angle (measured from horizontal).  (Ref: diagram below)

Also note: the correct gear angle is to the contact spot on the scale – not necessarily the leg itself.

 

 

Thus (in this case), the Torque = Moment Arm X Force (on the scale) X 1/Cos(gear angle)

 

 

However, if you were to use the vertical gear aircraft, the gear geometry is already perpendicular to the moment arm.  Thus, the scale would measure the complete (correct) force vector (no correction factor needed). 

 

 

Thus (in this case), the Torque = Moment Arm X Force (on the scale).

 

 

In both cases the scales will read the same.  How can this be???

 

Note: the moment arm (as measured) is shorter for the vertical gear aircraft.  The “magic” is that the slant gear correction factor (trigonometry for decomposing the vertical and horizontal force components) is the same as the trigonometry that affects the length of the respective moment arms.  Thus, correction factor is “already included” in the Moment Arm of the Vertical Gear scenario.

 

 

Of course the actual gear configuration doesn’t really matter since “the scale doesn’t know”.  So, if you want to use the force measurement directly off the scale, you need to use the horizontal distance from the centerline as the moment arm (similar to the vertical gear example above).  You can do this on any gear configuration.

 

Please comment on any corrections and/or improvements to this attempted explanation.

 

Rick Titsworth

rtitsworth@mindspring.com

 

 

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