Return-Path: Sender: (Marvin Kaye) To: lml@lancaironline.net Date: Wed, 26 Nov 2003 00:15:37 -0500 Message-ID: X-Original-Return-Path: Received: from gh-mail.centurytel.net ([209.206.160.252] verified) by logan.com (CommuniGate Pro SMTP 4.1.8) with ESMTP id 2772973 for lml@lancaironline.net; Tue, 25 Nov 2003 23:52:10 -0500 Received: from Downstairs (pppoe--69.29.33.156-rb.gh.centurytel.net [69.29.33.156]) by gh-mail.centurytel.net (8.12.10/8.12.10) with SMTP id hAQ4qAlt010672 for ; Tue, 25 Nov 2003 22:52:11 -0600 (CST) X-Original-Message-ID: <002701c3b3d9$099ec0e0$0100a8c0@Downstairs> From: "Robert Smiley" X-Original-To: "Lancair Mailing List" References: Subject: Re: [LML] Re: Help wanted with rudder/aileron trim tabs X-Original-Date: Tue, 25 Nov 2003 20:52:04 -0800 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0024_01C3B395.FB3FFE80" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2800.1158 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1165 This is a multi-part message in MIME format. ------=_NextPart_000_0024_01C3B395.FB3FFE80 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable I have not trim tab at all and the 360 flies straight and true center = ball level and up to 30 degree banked turns. Just make sure that that = the vertical stab and rudder are symetrical with no assymytrical lift = and you will be fine. Bob Smiley N94RJ ------=_NextPart_000_0024_01C3B395.FB3FFE80 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable

I have not trim tab at all and the 360 = flies=20 straight and true center ball level and up to 30 degree banked = turns. Just=20 make sure that that the vertical stab and rudder are symetrical = with no=20 assymytrical lift and you will be fine.

Bob Smiley

N94RJ

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