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Posted for Jason beaver <jason@jasonbeaver.com>:
That won't work as one of the 10k resistors will be in parallel with the lamp, and the resulting voltage at the middle of the two 10k resistors would be well below the halfway point.
e.g. for a 60 ohm lamp resistance (from Eric's earlier example), the effective resistance of the lamp/10k resistor in parallel would be roughly 59.6 ohms:
1/x = 1/10000 + 1/60
This would put the voltage across the lamp at about 0.07 volts:
v = 59.6/10059.6 * 12
jason
I wonder if you'd be better off splitting the voltage. For example, put two 10k resisters between 12V and ground, then pick up 6v between the resisters and ground.
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