Return-Path: Sender: (Marvin Kaye) To: lml@lancaironline.net Date: Wed, 05 Nov 2003 10:51:11 -0500 Message-ID: X-Original-Return-Path: Received: from tomts25-srv.bellnexxia.net ([209.226.175.188] verified) by logan.com (CommuniGate Pro SMTP 4.1.6) with ESMTP id 2710828 for lml@lancaironline.net; Wed, 05 Nov 2003 10:27:40 -0500 Received: from x6f5h0 ([67.69.58.60]) by tomts25-srv.bellnexxia.net (InterMail vM.5.01.06.05 201-253-122-130-105-20030824) with SMTP id <20031105152718.MCJL15340.tomts25-srv.bellnexxia.net@x6f5h0> for ; Wed, 5 Nov 2003 10:27:18 -0500 X-Original-Message-ID: <008a01c3a3ca$65e47c60$6d00a8c0@x6f5h0> From: "ian crowe" X-Original-To: "Lancair Mailing List" Subject: Ohm's law X-Original-Date: Wed, 5 Nov 2003 10:26:57 -0800 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0087_01C3A387.5774F120" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2800.1158 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1165 This is a multi-part message in MIME format. ------=_NextPart_000_0087_01C3A387.5774F120 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Can one of you erudite gentleman help a poor mechanical man? I have an low voltage light that is too bright. At night when I lower = the gear it tends to flash and upset my night vision. Right now the = bulb is out of it, which is good for the vision and bad for the warning! = I would like to dim that bulb. How do I go about calculating the value of the series resistance in ohms = required and the wattage of the resistance? I used to be able to do = this at high school but a lot of years have intervened and I forget. I = can measure the resistance of the bulb, the voltage is 12volts and where = do I go from there? Thanks Ian Crowe C-FKRO LC2 90 odd hours and counting ------=_NextPart_000_0087_01C3A387.5774F120 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
Can one of you erudite gentleman help a = poor=20 mechanical man?
 
I have an low voltage light that is too = bright.  At night when I lower the gear it tends to flash and upset = my=20 night vision.  Right now the bulb is out of it, which is good for = the=20 vision and bad for the warning!  I would like to dim that=20 bulb.
 
How do I go about calculating the value = of the=20 series resistance in ohms required and the wattage of the = resistance?  I=20 used to be able to do this at high school but a lot of years have = intervened and=20 I forget.  I can measure the resistance of the bulb, the voltage is = 12volts=20 and where do I go from there?
 
Thanks
 
Ian Crowe
C-FKRO
LC2 90 odd hours and=20 counting
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