Return-Path: Received: from [24.50.193.42] (HELO biggy) by logan.com (CommuniGate Pro SMTP 4.1b7) with ESMTP-TLS id 2402996 for lml@lancaironline.net; Wed, 04 Jun 2003 23:50:23 -0400 Message-ID: <00de01c32b15$95f07fe0$663b3690@logan.com> From: "Rob Logan" To: "Lancair Mailing List" Subject: Fw: [LML] Re: TSIO 550 Rich or Lean of Peak? Date: Wed, 4 Jun 2003 23:50:19 -0400 MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 7bit X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2800.1158 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1165 From: "Shannon Knoepflein" I feel that is bunk. I'm no ME thermo genius, but here is my simple calculation. We need to figure out how much heat is removed by the air or the gas, and my simple mind says a specific heat capacity calculation would give us this. First, assumptions (estimates, lets not get too caught up in exact numbers): Peak is about 15:1 AFR ROP, lets set it at 12:1 AFR LOP, lets likewise set it at 18:1 AFR On the ROP side, we have 12/1=15/x, or x=1.2, or 0.2 extra parts of gasoline On the LOP side, we have 18-15, or 3 extra parts of air Energy = (temperature change)*(parts)*(specific heat capacity) SHCoxygen=0.22 SHCgasoline=2.22 So, disregarding the temperature change as I really don't know what it is, 0.22*3 parts air=0.66 and 2.22*0.2 parts gasoline=0.44 I'm really not sure if I'm anywhere close to making any sense here. I'm sure some ME can step in and set it straight. However, here is the bottom line. CHT's are lower for LOP, that is proven, which also mean the valve seats and valves are cooler for LOP. This means air carries away more heat than the gasoline, which to me seems to disprove your theory below. Now, running "leaner" or "not lean enough" could certainly burn valves, as the highest CHT's (and valve temp) occurs at about 50-70 ROP, so if you are running there at high power, look out. Running 70 LOP puts you way out of this danger zone. Heat is heat, if the CHT's are cooler, the valve is cooler, and something is carrying that heat away. The only change is extra air versus extra gasoline, so I have to believe the air works better, and creates no danger to burning a valve. Please someone that knows more shed some light on this. Shannon