Return-Path: Received: from [24.25.9.101] (HELO ms-smtp-02-eri0.southeast.rr.com) by logan.com (CommuniGate Pro SMTP 4.2b6) with ESMTP id 243148 for flyrotary@lancaironline.net; Sun, 04 Jul 2004 23:25:31 -0400 Received: from EDWARD (clt25-78-058.carolina.rr.com [24.25.78.58]) by ms-smtp-02-eri0.southeast.rr.com (8.12.10/8.12.7) with SMTP id i653OvNs027176 for ; Sun, 4 Jul 2004 23:24:58 -0400 (EDT) Message-ID: <001201c4623f$a9308ed0$2402a8c0@EDWARD> From: "Ed Anderson" To: "Rotary motors in aircraft" References: Subject: Re: [FlyRotary] Re: Questions.. Date: Sun, 4 Jul 2004 23:25:03 -0400 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_000F_01C4621E.21E5B660" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2800.1409 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1409 X-Virus-Scanned: Symantec AntiVirus Scan Engine This is a multi-part message in MIME format. ------=_NextPart_000_000F_01C4621E.21E5B660 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Re: [FlyRotary] Re: Questions..Ok, Bulent I was not certain whether you were talking area or volume. As I = mentioned, the two GM cores give approx 2*(95*3.5) =3D 665 cubic inches. = Not saying this is the minimum you will need, however, that amount of = area and core has been shown to be adequate for cooling of the 13B. 458 = cubic inches is about 31 % smaller in cubic volume than the two cores, = so you might be a leaning a bit on the low side there. The smaller your = core, the more crucial the ducting is to get maximum cooling = effectiveness, so 458 will likely put a premium on your duct and = diffuser. On the other hand, if 458 is adequate then we will have = another data point. There is no doubt in my mind that your 458 cubic inches will easily cool = a 13B at cruise airspeeds, its the climbout that would concern me. My = 0.02. Ed Ed Anderson RV-6A N494BW Rotary Powered Matthews, NC ----- Original Message -----=20 From: Bulent Aliev=20 To: Rotary motors in aircraft=20 Sent: Sunday, July 04, 2004 11:05 PM Subject: [FlyRotary] Re: Questions.. > 3 For the water radiator I'm planning of using a core 3 times the = size of > the oil cooler. Does anybody think that it will be too small? If you are talking core surface area the oil cooler is approx 19x4 = =3D 76 sq inch. so 3 times that would be 228 sq inch. Two of the GM evaporator cores will give you 95x2 =3D 190 sq inches so = the area sounds OK. How about the core volumn? Yes, thickness does play = a part in cooling. The two gm cores have a core volumn of 2x( 9x10x3.5) = =3D 630 cubic inches. Just for a point of reference. Ed, The oil cooler has 2" thick core so, 76 sq inches x 2 =3D152 cubic = inches. Rad. will be 152 x 3=3D458cubic inches. Bulent ------=_NextPart_000_000F_01C4621E.21E5B660 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Re: [FlyRotary] Re: Questions..
Ok, Bulent
 
  I  was not certain = whether you=20 were talking area or volume.  As I mentioned, the two GM cores give = approx=20 2*(95*3.5) =3D 665 cubic inches.  Not saying this is the minimum = you will=20 need, however, that amount of area and core has been shown to be = adequate for=20 cooling of the 13B.  458 cubic inches is about 31 % smaller in = cubic volume=20 than the two cores, so you might be a leaning a bit on the low = side=20 there.  The smaller your core, the more crucial the ducting is to = get=20 maximum cooling effectiveness, so 458 will likely put a premium on your = duct and=20 diffuser.  On the other hand, if 458 is adequate then we will have = another=20 data point.
 
There is no doubt in my mind that = your 458=20 cubic inches will easily cool a 13B at cruise airspeeds, its the = climbout that=20 would concern me. My 0.02.
 
 
Ed
 
 
Ed Anderson
RV-6A N494BW Rotary=20 Powered
Matthews, NC
----- Original Message -----
From:=20 Bulent=20 Aliev
Sent: Sunday, July 04, 2004 = 11:05=20 PM
Subject: [FlyRotary] Re:=20 Questions..



> 3 For the water = radiator I'm=20 planning of using a core 3 times the size of
> the oil cooler. = Does=20 anybody think that it will be too small?

If you are=20 talking core surface area the oil cooler is approx 19x4 =3D 76 sq = inch.=20  so 3 times that would be 228 sq inch.  Two
of the GM=20 evaporator cores will give you 95x2 =3D 190 sq inches so the area = sounds OK.=20  How about the core volumn? Yes, thickness does play a part in = cooling.=20  The two gm cores have a core volumn of 2x( 9x10x3.5) =3D 630 = cubic=20 inches. Just for a point of=20 reference.


Ed,
The oil = cooler has=20 2=94 thick core so, 76 sq inches x 2 =3D152 cubic inches.  Rad. = will be 152 x=20 3=3D458cubic inches.
Bulent = ------=_NextPart_000_000F_01C4621E.21E5B660--