X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from mail-vx0-f180.google.com ([209.85.220.180] verified) by logan.com (CommuniGate Pro SMTP 5.4c2o) with ESMTPS id 4874108 for flyrotary@lancaironline.net; Thu, 17 Feb 2011 16:18:32 -0500 Received-SPF: pass receiver=logan.com; client-ip=209.85.220.180; envelope-from=afm528@gmail.com Received: by vxb41 with SMTP id 41so1682167vxb.25 for ; Thu, 17 Feb 2011 13:17:57 -0800 (PST) DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=gamma; h=domainkey-signature:from:to:references:in-reply-to:subject:date :message-id:mime-version:content-type:x-mailer:thread-index :content-language; bh=bUpcDaVZEaTRz+RFMIwDnSPAYYgtk+YQKexm+kOoeEs=; b=j3LExw7MukfnZciO8+KfFXb/6G4n1K9tgT+IAsTgoINwRtaZQ8mMrfSfxgkm8OhdI/ FHJxYeDVNe5Q57XMIF9u1ZnvRQ3IVeZyY3gg+MRf/LvvmKOv1gLr8dkBZJPEczIUBBdj 2nDCHu/Sj3uGQNCNuXRX7Na9fy3ygNjKbvDfs= DomainKey-Signature: a=rsa-sha1; c=nofws; d=gmail.com; s=gamma; h=from:to:references:in-reply-to:subject:date:message-id:mime-version :content-type:x-mailer:thread-index:content-language; b=N/2zHk0PbXN0omGTu+1aJ5/m+MiRey8YNzrszxmixgVoAXRkK8HpYA82QdBZyMEBiD 7j5er/QoaVw58Wd8jglEcGhajHN+pE8k+N11RakBYEAhc7OZUOLxRv5u9hUjJue40qXv B6+gC4VO/8tdoOfyXsVjjuQylyue6+gYPmIi8= Received: by 10.52.157.100 with SMTP id wl4mr585585vdb.190.1297977476127; Thu, 17 Feb 2011 13:17:56 -0800 (PST) Return-Path: Received: from MichaelHP (c-67-188-227-32.hsd1.ca.comcast.net [67.188.227.32]) by mx.google.com with ESMTPS id b5sm649193vcx.4.2011.02.17.13.17.54 (version=TLSv1/SSLv3 cipher=OTHER); Thu, 17 Feb 2011 13:17:54 -0800 (PST) From: "Michael McMahon" To: "'Rotary motors in aircraft'" References: In-Reply-To: Subject: RE: [FlyRotary] Re: Pressure increase from ram air Date: Thu, 17 Feb 2011 13:18:03 -0800 Message-ID: <06f201cbcee8$2b1593c0$8140bb40$@gmail.com> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_06F3_01CBCEA5.1CF4EBD0" X-Mailer: Microsoft Outlook 14.0 Thread-Index: AQMO8uS7/HLfkCspqA0OB+i99NKKrJF/6oBg Content-Language: en-us This is a multipart message in MIME format. ------=_NextPart_000_06F3_01CBCEA5.1CF4EBD0 Content-Type: text/plain; charset="utf-8" Content-Transfer-Encoding: quoted-printable Thanks Brian! =20 From: Rotary motors in aircraft [mailto:flyrotary@lancaironline.net] On = Behalf Of bktrub@aol.com Sent: Thursday, February 17, 2011 1:16 PM To: Rotary motors in aircraft Subject: [FlyRotary] Re: Pressure increase from ram air =20 Standard day sea level pressure is 14.7 PSI or 29.92 inches of mercury. = 1 inch of mercury is .49 PSI, 2 inches is .98 or ~ 1 psi. Brian Trubee =20 -----Original Message----- From: Michael McMahon To: Rotary motors in aircraft Sent: Thu, Feb 17, 2011 12:35 pm Subject: [FlyRotary] Re: Pressure increase from ram air Please forgive me if this is obvious, but is it possible to convert = 2=E2=80=9D of mercury to X lbs. of boost, as in a turbo? I=E2=80=99d = love to see the math if anyone can show me. =20 =20 Thanks, =20 Mike =20 From: Rotary motors in aircraft [ = mailto:flyrotary@lancaironline.net] On Behalf Of Tracy Sent: Thursday, February 17, 2011 11:09 AM To: Rotary motors in aircraft Subject: [FlyRotary] Re: Pressure increase from ram air =20 Yes, 2" of Hg, but that was at top speed when racing (224 mph), not = cruise. My ram air inlet is about 1" behind the prop which may affect = the amount. Tracy On Thu, Feb 17, 2011 at 1:33 PM, Ernest Christley < = echristley@att.net> wrote: Tracy, you've said before that you can estimate 2" of pressure increase from ram air at cruise. Is that 2" of mercury? -- Homepage: http://www.flyrotary.com/ Archive and UnSub: = = http://mail.lancaironline.net:81/lists/flyrotary/List.html =20 ------=_NextPart_000_06F3_01CBCEA5.1CF4EBD0 Content-Type: text/html; charset="utf-8" Content-Transfer-Encoding: quoted-printable

Thanks Brian!

 

From:= = Rotary motors in aircraft [mailto:flyrotary@lancaironline.net] On = Behalf Of bktrub@aol.com
Sent: Thursday, February 17, 2011 = 1:16 PM
To: Rotary motors in aircraft
Subject: = [FlyRotary] Re: Pressure increase from ram air

 

S= tandard day sea level pressure is 14.7 PSI or 29.92 inches of mercury. 1 = inch of mercury is .49 PSI, 2 inches is .98 or ~ 1 = psi.

B= rian Trubee

<= o:p> 

-= ----Original Message-----
From: Michael McMahon = <afm528@gmail.com>
To: Rotary motors in aircraft = <flyrotary@lancaironline.net>
Sent: Thu, Feb 17, 2011 12:35 = pm
Subject: [FlyRotary] Re: Pressure increase from ram = air

Please forgive me if this is obvious, but is it possible to convert = 2=E2=80=9D of mercury to X lbs. of boost, as in a turbo?  = I=E2=80=99d love to see the math if anyone can show me.  = <= o:p>

 <= o:p>

Thanks,<= o:p>

 <= o:p>

Mike<= o:p>

 <= o:p>

= From:= Rotary motors in aircraft [mailto:flyrotary@lancaironline.net] = On Behalf Of Tracy
Sent: Thursday, February 17, 2011 = 11:09 AM
To: Rotary motors in aircraft
Subject: = [FlyRotary] Re: Pressure increase from ram air<= o:p>

&= nbsp;

Y= es, 2" of Hg, but that was at top speed when racing (224 mph), not = cruise.  My ram air inlet is about 1" behind the prop which = may affect the = amount.

Tracy

O= n Thu, Feb 17, 2011 at 1:33 PM, Ernest Christley <echristley@att.net> = wrote:

<= br>Tracy, you've said before that you can estimate 2" of pressure = increase
from ram air at cruise.  Is that 2" of = mercury?

--
Homepage:  http://www.flyrotary.com/
Archive = and UnSub:   http://mail.lancaironline.net:81/lists/flyrotary/Lis= t.html<= o:p>

&= nbsp;

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