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Area of filler rods divided by total area.

 

I probably computed it wrong.

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So on that basis I’d estimate your filling ratio at about .13.  For a filling ratio of 0.5 with .05 diameter tubes on a square pitch you’d need a center to center distance on the tubes of 0.63.

Just realized there is a typo in this part – should 0.5 diameter. I’m sure you noticed that.

Al

One square, drawn from the centers of 4 tubes includes the area of one tube, which is about 0.2. So the total area of the square needs to be 0.4, so the length of a side is the square root of 0.4, = 0.6325.  The tubes would be little more than 1/8” apart.

 

Or am I missing something?

 

Al G