Return-Path: Sender: (Marvin Kaye) To: flyrotary Date: Tue, 22 Oct 2002 00:23:53 -0400 Message-ID: X-Original-Return-Path: Received: from imo-d09.mx.aol.com ([205.188.157.41] verified) by logan.com (CommuniGate Pro SMTP 4.0) with ESMTP id 1841870 for flyrotary@lancaironline.net; Mon, 21 Oct 2002 23:38:41 -0400 Received: from Wschertz2@aol.com by imo-d09.mx.aol.com (mail_out_v34.13.) id q.142.eab356 (3890); Mon, 21 Oct 2002 23:38:33 -0400 (EDT) From: Wschertz2@aol.com X-Original-Message-ID: <142.eab356.2ae62238@aol.com> X-Original-Date: Mon, 21 Oct 2002 23:38:32 EDT Subject: Re: [FlyRotary] Re: Electric Water Pumps X-Original-To: flyrotary@lancaironline.net X-Original-CC: wschertz@anl.gov MIME-Version: 1.0 Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit X-Mailer: AOL 5.0 for Windows sub 140 In a message dated 10/21/2002 7:07:07 AM Central Daylight Time, n268bl@charter.net writes: > Subj: [FlyRotary] Re: Electric Water Pumps > Date: 10/21/2002 7:07:07 AM Central Daylight Time > From: n268bl@charter.net (Bill Eslick) > Sender: flyrotary@lancaironline.net > Reply-to: flyrotary@lancaironline.net > To: flyrotary@lancaironline.net > > ..............................So to remove the waste heat from the engine, > operating at 180 horsepower, > there needs to be a 47 Degree temperature rise across the engine and a 47 > Degree temperature drop across the radiator. > .................................. > > *************************************************** > > This may not be the case in actual practice. I estimate my engine at about > 140 HP at this point, and running this thru the equations gives me about a > 36 degree drop required. (Did I do that correctly?) > > I can climb out on 100+ degree days and the temp drop across my (GM) cores > is only 10-15 degrees. Cooling is stable at that point at around 190 > degrees. In my first 100 hours at many temps and altitudes, the drop is > always around 10 to 15 degrees. > > I am using the CHT probes of my EIS clamped to the exit tubes of the cores > to get these temps. They are wrapped with firesleeve to ward off other > sources of heat. > > Bill Eslick > > > > >> Homepage: http://www.flyrotary.com/ > ------------------ ----------------------------------- Your measurements of the delta T indicate that you have much greater flow rate than 80 liters per minute. A higher flow rate means that the delta T will be less. Your arithmetic is correct, at 80 liter/min flow, you should expect 36 degree delta T. Since you are getting 15 degree delta T, your flow rate is about 36*80/15 = 192 liter/minute, or 50 gallons/minute (which is about what Powersport found they needed). Everyone please bear in mind that I have nothing against Electric Water Pumps, but I firmly believe in things like thermodynamics, heat capacity, and pump pressure curves. Too many engineering courses I guess -- I have only used the data published by Davies-Craig and Mazda in my calculations. Bill Schertz KIS Cruiser #4045