Let me see if I've got this
right. "q" is dynamic pressure, correct? As best I recall the
equation for dynamic pressure is 1/2pV^2 with p being air density and V
velocity.
So if I understand you
correctly, it appears that even for IAS - the case is we are
using TAS (actual velocity of air molecules - or aircraft) to generate
the dynamic pressure in the pitot tube that gives us an indication -
we know as IAS? So I guess its correct to say IAS is a reflection of "q"
but the indication is actually a result of air density and TAS,
Correct??
I certainly
understand your argument for TAS as being the speed of the molecules and
therefore the rate at which they carry away heat. Its just I
would have bet money that if you wanted to test the effects of different ambient
tempts on a core, you would ensured that they both saw the same dynamic
pressure. In order to do that, of course, at higher altitude you
would need a greater true airspeed (due to the lower density) in
order to get the same IAS (dynamic pressure) as you would have at a lower
altitude (denser air with less TAS).
But, you live and
learn.
Getting older and none the swifter
{:>)
Ed A
Sounds like you got it. There is no apples to
apples in this case. The only apples to apples is same pressure, lower T1 same
heat rejection. Of course density will be higher and Dt will be
lower.
The only apples I'm interested in is the same fuel
flow (heat rejection) Everything else will be different and I want to know how
much so I can make a guestimate of heat exchanger effectiveness.
What method did you use in your math models for the
heat exchangers? LMTD or NTU?
Monty