Tom,
I don't really think anyone can accurately
make a generalization like that. Certainly a PP 13B (such as power
sports) which reportedly produces 215 HP produces more power than a carb
360 Lycoming. A street ported well tuned 13B will certainly produce
180HP. But, given any two specific engines and depending on how well their
induction/exhaust, etc. are set up, you could have one or the other producing
the greater HP.
But, if someone has specific data that shows the
360 produces more power, then I would certainly like to know about
it.
Ed A
----- Original Message -----
Sent: Thursday, February 10, 2005 9:14
AM
Subject: [FlyRotary] Re: : Same HP = Same
Air Mass <> same air Velocity II [FlyRotary] Re: Ellison, the missing
piece
It's my understanding that NA non-renesis rotary installations
produce less power than 360s, Perry Mick might have a word on this.
Warning
top poster, who cuts the post size down.
A hopothises for your
examination.
A 360 Lyc does not produce the same power as a
rotary.
If true, then the Ellison card may not get enough
air.
If not true, then there is no real reason why the Ellison cannot
feed a rotary.
Ed, I understand your math, but even if the local
inlet velocity is much higher, we dont care. the velocities adverage out
to the same, as the volume of air = velocity * carb area.
If the
velocities are higher, the rotary consumes more air, and makes
more power.
Eric
----- Original Message ----- From: "Ed
Anderson" To: "Rotary motors in aircraft"
Sent: Thursday, February 10, 2005 8:31
AM Subject: [FlyRotary] : Same HP = Same Air Mass <> same air
Velocity II [FlyRotary] Re: Ellison, the missing piece
Good
question, Tom.
That interpretation did occur to me. I think the
answer depends on your assumptions, IF using commonly accepted formulas
for calculating air flow vs rpm and displacement (and considering both
are positive displacement pumps) - then the 360 CID lycoming turning 2800
rpm and the rotors in the rotary turning 2100 rpm (6300 rpm E shaft)
ingest the same total quantity of air in one minute - approx 291 CFM. In
comparing the two engines, its accepted that you compare them over the
standard 720deg 4 stroke cycle - that means that 4 of the rotary faces
have gone through their cycle in the same 720 deg of
rotation.
But, assuming the formulas are correct, then they both end
up with the same amount of air in the engine to create the same HP. I
think my math is correct on the smaller/unit displacement and longer
period of rotation for the rotary for the same intake of air. However, in
both cases the air flow is pulsating and pulsating differently. So if the
total displacement for the rotary over that 720 deg is less than the
Lycoming and the time it takes to complete that rotation is slower AND
you still ingest the same amount of total Air then the only way I can see
that happening is the velocity of the air in the rotary's intake has to
be considerably higher than in the Lycoming.
The only other
alternative answer I see if that the commonly accepted formula for
comparing the rotary to the reciprocating 4 stroke is incorrect (I got
beat about the head mercilessly by a number of respected rotary experts
challenging that formula , so I wont' go there again (at least not now
{:>)).
Air Flow = Total Displacement * RPM/(2 - accounting for
only every other cylinder sucking on each rev * 1728 (conversion of cubic
inches to cubic feet) = TD*RPM/(2*1728)
For the 360 CID Lycoming
at 2800 rpm, Air Flow = 360*2800/(2*1728) = 291.66 CFM
Using the
commonly accepted notion that a rotary is equivalent to a 160 CID 4
stroke reciprocating engine because of the 4 faces of 40 CID that
complete there cycle in 720 deg.
For the 160 CID Rotary at 6000
rpm, Air Flow = 160 * 6300/(2*1728) = 291.66 CFM
So if both ingest
the 291 CFM and the rotary has less total displacement (over 720 deg)
then disregarding any of my math on rotation period differences you still
have to account for why the rotary can ingest the same amount of air with
less displacement. (Now I must admit I have my suspicions about the
commonly accepted (racing approved) formula for the rotary. However, if
my suspicions about the rotary formula are correct, it would make the
rotary even more efficient at ingesting air - so I won't go there
{:>)).
If my logic and calculations are correct then this implies
the Ve of the rotary is considerably better than the Lycoming and is
great than 100%. I mentioned a few of the reasons why the Ve of the
rotary may indeed be better in the previous message.
Now, its
possible that the stories about the Ellison not working well on
the rotary is just that - a story OR there could be a plausible physical
reason as I have poorly attempted to
present.
Ed
----- Original Message ----- From:
Tom To: Rotary motors in aircraft Sent: Wednesday, February 09, 2005
11:54 PM Subject: [FlyRotary] Re: Same HP = Same Air Mass <> same
air Velocity [FlyRotary] Re: Ellison, the missing
piece
Ed,
>The rotary has 40 CID displacement per face
and 2 facesx 2 rotors = 4*40 or 160 CID for one rev. So the rotary has
22% less displacement per revolution and the longer rotation
period.<
and
>So if the rotary has less displacement of
the sucking component and must take 25% longer for each revolution.
Therefore the only way it can obtain an equal amount of air is for the
intake air to have a higher velocity than the Lycoming
does.<
Isn't 'displacement' equal to the amount of air needing to
be ingested? So 22% less displacement equates to 22% less air and the
rotarys longer rotation period gives it more time for air to push in? And
then the intake air velocity should be lower?
>>
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